Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
The circumference of the circle is = 2 x pi x 6 = 37.7cm
To find the arc = 360 divided by 169 = 2.13
The arc = 37.7 divided by 2.13 = 17.69 cm
85 is a <span>26.865671641791% higher than 67
Hope this helps!!
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When x is zero there will never be an interception of the line as x=0 is an asymtope
Answer:
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Step-by-step explanation:
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