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3 years ago

Four equivalent expressions of 36 mince 9

Mathematics

2 answers:

Vlad [161]3 years ago

4 0

36-9
-9+36
1 (36-9)
36-(3×3)

soldi70 [24.7K]3 years ago

4 0

The answer is 27. Making 30 - 3, 9 x 3, 20 + 7, and 25 + 2 all valid.

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Jason deposited $18 000 in a bank that offers an interest rate of 5% per annum compounded

8_murik_8 [283]

Answer:

$1995.97.

Step-by-step explanation:

Amount in bank after 20 days =

18000(1 + 0.05/365)^20

= $18049.38

So H = 18049.38 - 16093.41

= $1995.97.

3 0

2 years ago

Tamita is making popcorn balls. She has 18.5 ounces of syrup. The recipe says that each batch of popcorn balls needs 4 ounces of

bija089 [108]

Answer:

4 batches

Step-by-step explanation:

Total syrup made by Tamita = 18.5 ounces

Amount of ounces per batch = 4 ounces

If 1 batch = 4 ounces

x batches = 18.5 ounces

Cross multiply

4 * x = 18.5

x = 18.5/4

x = 4.625

Hence she can only make 4 batches of syrup

5 0

3 years ago

Please help i have a c

Sergeu [11.5K]

Answer: the last option

Step-by-step explanation:

the top right is I, the top left is II, the bottom left is III, and the bottom right is IV

6 0

3 years ago

Read 2 more answers

What is 2x – 3 < 7 and 5 – x ≤ 8?

iren2701 [21]

Answer:

$\begin{bmatrix}x$

Step-by-step explanation:

$2x -3 < 7 \\ 5 - x \leq 8\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:2x-3$

7 0

4 years ago

Read 2 more answers

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$