Question

*PLEASE help* P(A)= 98%, find p(not A)

Answer 1

$P(A')=1-P(A)=100\%-98\%=2\%$

Answer 2

Hi there!

Given P(A) = 98%

To find P(not A) we must first convert P(A) into a decimal. To find 98% as a decimal we only need to divide by 100.
$98\% = 98 \div 100 = 0.98$

Now we know the following:
P(A) = 0.98. To find P(not A) we need to subtract P(A) from 1.

P(not A) = $1 - P(A)$
P(not A) = $1 - 0.98 = 0.02$

Change into a percentage by multiplying the decimal by 100.
P(not A) = P(A') = $0.02 \times 100 = 2\%$

Hope this helps you!