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Mkey [24]
3 years ago
10

A survey asked a group of students to choose their favorite type of sport from the choices of soccer, softball, basketball, and

others. The results of the survey are shown in the graph. Based on the graph, how many students in a class of 84 students would be expected to choose a sport other than soccer, softball, or basketball as their favorite type of sport?
Mathematics
1 answer:
jolli1 [7]3 years ago
3 0
The answer would be 12 students. 8+4+6+3=21. 
     84 divided by 21 would = 4. 
  3 students times 4 = 12 students
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In a given right triangle, If 0 º < x < 90 º and cos x = √ 3 / 2, then sin x = ?
nordsb [41]

Answer:

  1/2

Step-by-step explanation:

The "Pythagorean relation" between trig functions can be used to find the sine.

<h3>Pythagorean relation</h3>

The relation between sine and cosine is the identity ...

  sin(x)² +cos(x)² = 1

This can be solved for sin(x) in terms of cos(x):

  sin(x) = √(1 -cos(x)²)

<h3>Application</h3>

For the present case, using the given cosine value, we find ...

  sin(x) = √(1 -(√3/2)²) = √(1 -3/4) = √(1/4)

  sin(x) = 1/2

__

<em>Additional comment</em>

The sine and cosine of an angle are the y and x coordinates (respectively) of the corresponding point on the unit circle. The right triangle with these legs will satisfy the Pythagorean theorem with ...

  sin(x)² + cos(x)² = 1 . . . . . . where 1 is the hypotenuse (radius of unit circle)

A calculator can always be used to verify the result.

6 0
1 year ago
Which of the following is a complex number?<br> -7<br> 2 + StartRoot 3 EndRoot<br> 4 + 9i<br> Pi
zepelin [54]
Second to last one is my guess
8 0
4 years ago
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Part 1 Write your own real-world scenario where the Pythagorean Theorem can be applied to find a missing piece. You may choose t
kondor19780726 [428]
I think this answers all the parts

Hope this helped :)

7 0
3 years ago
A(n - 3) +8= bn for n please help me
Papessa [141]

Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

We can see n is a common factor on rigth side in bn-an.

Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}

On right (b-A) paranthiss cancelled and we get n on right side.

\frac{(-3A+8)}{(b-A)} =n   Final answer.

So, that would be our final answer

n = (-3A+8)/(b-A)

7 0
3 years ago
−8−1+4 ⋅ 2 find the answer to this equation
jeyben [28]

Answer:

-1

Step-by-step explanation:

6 0
3 years ago
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