All categories

3 years ago

Find the number that makes 4:12 equivalent to 28:__.

Mathematics

2 answers:

babunello [35]3 years ago

7 0

Answer:

Step-by-step explanation:

4 : 12 = 28 : x

If you do something to one side you have to do the same thing to the other side.

28 ÷ 4 = 7

12 × 7 = 84

Hope This Helps :)

guapka [62]3 years ago

6 0

Answer:

Step-by-step explanation:

We can set up a proportion using fractions.

$\frac{4}{12} = \frac{28}{x}$

Now, let's cross multiply by multiplying 12 and 28 then dividing by 4.

$12\cdot28=336\\\\336\div4=84$

Hope this helped!

You might be interested in

Education researchers are interested in the workload expectations of freshmen at a local university. Since all of the freshmen a

Olegator [25]

Answer: Cluster Sampling

Step-by-step explanation: I just took this test and got it correct :)

7 0

2 years ago

Please help ** revised version ** will give 13 points

hammer [34]

If each math book is 0.75 of a inch wide you would do 18 divided by 0.75= 24. 24 books width can fit into the 18 inches.

3 0

3 years ago

What does a obtuse angle look like

AfilCa [17]

Answer:

90 degrees and up

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

2 years ago

Kenya exchanges $200 for euros (€). Suppose the conversion rate is €1 = $1.321. How many euros should Kenya receive?

ohaa [14]

€151.40 would be the outcome i believe

7 0

3 years ago

Read 2 more answers