Answer:
I would rather use their multiples.
Step-by-step explanation:
With 13 and 14, neither number has many factors (and few prime factors, for that matter) so factoring would be pretty much useless. If you wanted to use the prime factors of 14 (7 and 2) multiplying either of them by 13 would not give you the LCM. Actually the LCM is just 13*14 which is 182.
Good luck!
When Jamie has $200 to purchase skateboard equipment, he will have spent more than 50 percent.
<h3>How to calculate the percentage?</h3>
From the information given, the total amount spent will be:
= $100 + $60 + $30 + $20 + $20 + $50 + $115
= $395
Since Jamie has $200 to purchase skateboard equipment, the percentage will be:
= 200/395
= 0.51
= 51%
Learn more about percentages on:
brainly.com/question/24304697
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Answer:
Step-by-step explanation:
y = 2x - 1
y = x - 8 ------ (i)
substitute y = 2x - 1 in equation (i)
2x - 1 = x - 8
2x = x - 8 + 1
2x = x - 7
2x - x = -7
x = -7
Substitute x value in equation (i)
y = -7 - 8
y = -15
Answer:
Step-by-step explanation
Hello!
Be X: SAT scores of students attending college.
The population mean is μ= 1150 and the standard deviation σ= 150
The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.
If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:
H₀: μ = 1150
H₁: μ ≠ 1150
α: 0.05
![Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)](https://tex.z-dn.net/?f=Z%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BSigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~~N%280%3B1%29)
The p-value for this test is 0.0949
Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.
I hope it helps!
