A menu offers a choice of 2 salads, 6 main dishes, and 5 desserts. How many different meals consisting of one salad, one main
dish, and one dessert are possible?
2 answers:
Answer:
60 different meals
Step-by-step explanation:
The possibilities of 1 salad = 2
The possibilities of 1 main dishes = 6
The possibilities of 1 desert = 5
Then we multiply all the types of posibilities together in other to have different meals consisting of one salad, one main dish, and one dessert
2*5*6 = 60
Cheers
Answer:
Answer is 60
Step-by-step explanation:
The possibility of a salad meal is =2
2C1 = 2
The possibility of a main dish = 6
6C1 = 6
The possibility of a dessert is = 5
5C1 = 5
So the total possibility is the multiplication of the three i.e
2*6*5 = 60
The principle applied is the combination principle.
Note that C stands for combination
You might be interested in
Answer:
T (2, 2)
U (4 , 0)
V (1, -2)
Step-by-step explanation:
The translation is (x + 5, y), meaning 5 is being added to the X-values and Y stays the same.
The Probability of winning is 5/8.
Answer:
Step-by-step explanation:
we know that
In the right triangle ABC of the figure
Applying the Pythagoras Theorem
substitute the given values
Solve for c
73 I believe I’m not sure
The formula of a slope:
We have the points A(-6, 6) and B(12, 3). Substitute:
Therefore we have .
Put the coordinates of the point B to the equation:
<em>add 2 to both sides</em>
Answer: