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evablogger [386]
3 years ago
15

A menu offers a choice of 2 ​salads, 6 main​ dishes, and 5 desserts. How many different meals consisting of one​ salad, one main

​ dish, and one dessert are​ possible?
Mathematics
2 answers:
ioda3 years ago
4 0

Answer:

60 different meals

Step-by-step explanation:

The possibilities  of 1 salad = 2

The possibilities  of 1 main dishes  = 6

The possibilities  of  1 desert = 5

Then we multiply all the types of posibilities together in other to have different meals consisting of one​ salad, one main​ dish, and one dessert

2*5*6 = 60

Cheers

Akimi4 [234]3 years ago
3 0

Answer:

Answer is 60

Step-by-step explanation:

The possibility of a salad meal is =2

2C1 = 2

The possibility of a main dish = 6

6C1 = 6

The possibility of a dessert is = 5

5C1 = 5

So the total possibility is the multiplication of the three i.e

2*6*5 = 60

The principle applied is the combination principle.

Note that C stands for combination

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ch4aika [34]

Answer:

Step-by-step explanation:

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=======================================================

Explanation:

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Algebraically, the reflection rule used can be written as

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