What is the third quartile of the following data set<br><br>
24,20,35,39,28,42,25,29,44,21,37
strojnjashka [21]
First, arrange the data:
20, 21, 24, 25, 28, 29, 35, 37, 39, 42, 44
You can use the formula 3/4 multiplied by the number of data + 1 to find the position of the 3rd quartile.
so it's going to be 3/4 x (11+1) = 9th position
the number in 9th position is 39 so that's the 3rd quartile
Step-by-step explanation:
20.48731511
round up and write your answer
4 times the sum of the least and greatest integers ⇒ 4(n + n +2) = 4n + 8
12 less than three times the least integer ⇒ 3n - 12
4n + 8 = 3n - 12
4n - 3n + 8 = 3n - 3n - 12
n + 8 - 8 = -12 - 8
n = -20
-20, -19, -18 are the integers and the least is -20
You use tan34=x/15
so x=15*tan(34degrees)
x=10.12 ft