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Keith_Richards [23]
2 years ago
13

Brainliest if correct

Mathematics
2 answers:
laila [671]2 years ago
7 0

Answer:

B.) V2/3

Step-by-step explanation:

Yuliya22 [10]2 years ago
3 0

   =sqrt(2) /3

sqrt(2/9)

We can split the sqrt(a/b) = sqrt(a)/ sqrt(b)

sqrt(2/9) = sqrt(2)/sqrt(9)

We know that the sqrt(9) is 3

             =sqrt(2) /3

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-3, -2, 1

Step-by-step explanation:

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2 years ago
The size of a laptop monitor is usually measured along the diagonal. A rectangular monitor is 12 inches long and 7 inches tall.
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16 inch is your answer 
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3 years ago
Read 2 more answers
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
2 years ago
In a recent study, volunteers who had 8 hours of sleep were three times more likely to answer questions correctly on a math test
kumpel [21]

Answer:

(c) the sample is amount of sleep the volunteers got in the study.

Step-by-step explanation:

sample: this is a small part that is intending to show what a big part is all about.

volunteer: a person who does something willingly.

6 0
3 years ago
Find the other endpoint of the line segment if:
Vesna [10]

Answer:

<em>( - 15, - 16 ) </em>

Step-by-step explanation:

Coordinates of midpoint are ( \frac{x_{1} +x_{2} }{2} , \frac{y_{1} +y_{2} }{2} )

( - 5 + x ) / 2 = - 10 ⇒ x = - 15

( 4 + y ) / 2 = - 6 ⇒ y = - 16

<em>( - 15, - 16 )</em>

5 0
2 years ago
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