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2 years ago

Brainliest if correct

Mathematics

2 answers:

laila [671]2 years ago

7 0

Answer:

B.) V2/3

Step-by-step explanation:

Yuliya22 [10]2 years ago

3 0

=sqrt(2) /3

sqrt(2/9)

We can split the sqrt(a/b) = sqrt(a)/ sqrt(b)

sqrt(2/9) = sqrt(2)/sqrt(9)

We know that the sqrt(9) is 3

=sqrt(2) /3

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What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3. 1.x - 3 y - 7 = 2.x -

Nutka1998 [239]

Answer:

x- 3y - 7=0

Step-by-step explanation:

the line in the slope-intercept form:

y= mx+b

m= 1/3 and point given (1, -2) by using which we find y-intercept:

b= y-1/3x
b= -2- 1/3*1= - 7/3

y= 1/3x- 7/3

General form of a line is: ax+by+c= 0

converting:

y= 1/3x- 7/3 ⇒ 3y= x- 7 ⇒ x- 3y - 7=0

5 0

3 years ago

The sprit club is making school jackets to sell. The cost c (in dollars) for silkscreening supplies and jackets is c=20x+270, wh

lys-0071 [83]

Answer:

The club must sell 18 jackets to break even

Step-by-step explanation:

Given:

C = 20x + 270

Where,

x = number of jackets

Equation for revenue R in terms of the number of jackets

Revenue = price × quantity

Price of the jacket = $35

Quantity of the jacket = x

Revenue = price × quantity

= 35 * x

R = 35x

Break even point is the point at which cost is equal to revenue, that is, no gain; no loss.

Cost = revenue

20x + 270 = 35x

270 = 35x - 20x

270 = 15x

x = 270 / 15

= 18

x = 18 jackets

The club must sell 18 jackets to break even

3 0

3 years ago

Read 2 more answers

HELP PLEASE I NEED A ANSWER ASAP

nata0808 [166]

Answer:

5x+6+48+81=180°

5x+135=180

5x=45

x=9

Step-by-step explanation:

I HOPE it will help you

8 0

3 years ago

Read 2 more answers

Could someone answer these 3 for me?

KengaRu [80]

Answer:

x=4.77

Angle 3=98.32 degrees

Angle 6= 81.68 degrees

Step-by-step explanation:

(Assuming these are parallel lines), Angle 3 and angle 5 are equal because they are alternate Angles. Therefore we can write the following equation to solves for x:

16x+22=3x+84 (angle 3=angle5)

Which we can now solve:

16x +22 - 22 - 3x=3x-3x+84-22

13x=62

13x/13=62/13

x=4.77 (2dp)

We can then use this x to calculate angle 3:

16(4.77)+22

76.33+22=98.32 degrees

Finally,

Angle 6 and angle 3 are interior angles, so they add up to 180 degrees.

So to find angle 6,we can just subtract angle 3 from 180:

180-98.32=81.68 degrees.

Hope this helped!

6 0

3 years ago

A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x overbar, is found

joja [24]

Answer:

(a) 80% confidence interval for the population mean is [109.24 , 116.76].

(b) 80% confidence interval for the population mean is [109.86 , 116.14].

(c) 98% confidence interval for the population mean is [105.56 , 120.44].

(d) No, we could not have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed.

Step-by-step explanation:

We are given that a simple random sample of size n is drawn from a population that is normally distributed.

The sample mean is found to be 113 and the sample standard deviation is found to be 10.

(a) The sample size given is n = 13.

Firstly, the pivotal quantity for 80% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 113

s = sample standard deviation = 10

n = sample size = 13

$\mu$ = population mean

Here for constructing 80% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 80% confidence interval for the population mean, $\mu$ is ;

P(-1.356 < $t_1_2$ < 1.356) = 0.80 {As the critical value of t at 12 degree

of freedom are -1.356 & 1.356 with P = 10%}

P(-1.356 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.356) = 0.80

P( $-1.356 \times }{\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.356 \times }{\frac{s}{\sqrt{n} } }$ ) = 0.80

P( $\bar X-1.356 \times }{\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.356 \times }{\frac{s}{\sqrt{n} } }$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X-1.356 \times }{\frac{s}{\sqrt{n} } }$ , $\bar X+1.356 \times }{\frac{s}{\sqrt{n} } }$ ]

= [ $113-1.356 \times }{\frac{10}{\sqrt{13} } }$ , $113+1.356 \times }{\frac{10}{\sqrt{13} } }$ ]

= [109.24 , 116.76]

Therefore, 80% confidence interval for the population mean is [109.24 , 116.76].

(b) Now, the sample size has been changed to 18, i.e; n = 18.

So, the critical values of t at 17 degree of freedom would now be -1.333 & 1.333 with P = 10%.

80% confidence interval for $\mu$ = [ $\bar X-1.333 \times }{\frac{s}{\sqrt{n} } }$ , $\bar X+1.333 \times }{\frac{s}{\sqrt{n} } }$ ]

= [ $113-1.333 \times }{\frac{10}{\sqrt{18} } }$ , $113+1.333 \times }{\frac{10}{\sqrt{18} } }$ ]

= [109.86 , 116.14]

Therefore, 80% confidence interval for the population mean is [109.86 , 116.14].

(c) Now, we have to construct 98% confidence interval with sample size, n = 13.

So, the critical values of t at 12 degree of freedom would now be -2.681 & 2.681 with P = 1%.

98% confidence interval for $\mu$ = [ $\bar X-2.681 \times }{\frac{s}{\sqrt{n} } }$ , $\bar X+2.681 \times }{\frac{s}{\sqrt{n} } }$ ]

= [ $113-2.681 \times }{\frac{10}{\sqrt{13} } }$ , $113+2.681 \times }{\frac{10}{\sqrt{13} } }$ ]

= [105.56 , 120.44]

Therefore, 98% confidence interval for the population mean is [105.56 , 120.44].

(d) No, we could not have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed because t test statistics is used only when the data follows normal distribution.

6 0

3 years ago