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3 years ago

Solve the system of equations by any method

Mathematics

1 answer:

Ann [662]3 years ago

3 0

Insert y and you get
X=0
Then insert x and you get
Y=-5

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Solve the equation (for n )

myrzilka [38]

Hello! Hopefully I will be able to clarify and answer your equation in a way that can help you understand better. Here are the steps...

N + 6/-4 = 10

N + 6 = -40

N = -40 - 6

N= -46

Hope this helped!

7 0

3 years ago

Read 2 more answers

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73

faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]

Therefore,

CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})$

Thus,

Lower limit of CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}})$

Lower limit of CI = $(98.3 - \frac{2.62\times0.73}{\sqrt{103}})$

Lower limit of CI = 98.11

and,

Upper limit of CI = $(Mean + \frac{t\times\sigma}{\sqrt{n}})$

Upper limit of CI = $(98.3 + \frac{2.62\times0.73}{\sqrt{103}})$

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F

7 0

2 years ago

Solution of the inequality y>1.9

Vedmedyk [2.9K]

The answer will be 2.0

6 0

2 years ago

BRAINLIEST BRAINLIEST!! Easy math ASAP

Katena32 [7]

First answer is (-2,2) second answer is (4,2)

3 0

2 years ago

Read 2 more answers

4 square root of 6<br> over square root of 2

NeTakaya

4 square root of 6 means 4 times $\sqrt{6}$
so the equation is $\frac{4 \sqrt{6} }{ \sqrt{2} }$
we can simplify this as a fraction
remember that $\sqrt{xy}= (\sqrt{x}) (\sqrt{y})$ so
$4 \sqrt{6}=4( \sqrt{3})( \sqrt{2})$ so it is now
$\frac{4 \sqrt{3}( \sqrt{2}) }{ \sqrt{2} }= (\frac{4 \sqrt{3}} {1} )( \frac{ \sqrt{2} }{ \sqrt{2} })= (\frac{4 \sqrt{3}} {1} )(1)=4 \sqrt{3}$

5 0

2 years ago