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grigory [225]
3 years ago
6

What is the solution to the equation 7,- 5* ++5

Mathematics
1 answer:
maw [93]3 years ago
5 0

Answer:

the answer to the problem is h=7

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55555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555
Mazyrski [523]

Answer:

i-

ok

Step-by-step explanation:

7 0
3 years ago
Independent random samples of vehicles traveling past a given point on an interstate highway have been observed on monday versus
quester [9]
Hi! 

To compare this two sets of data, you need to use a t-student test:

You have the following data:

-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph

-Wednesday n2=20;  </span>x̄2=56,3 mph; s2=4,4 mph

You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.



5 0
3 years ago
Find the lateral surface area of the cylinder. Round your answer to the nearest tenth.
Zarrin [17]

Answer:

= 2\pi \: r \: h \\ 2 \times \pi \times 4 \times 9 \\  = 226 .19 {cm}^{2}

Can I have the brainliest please?

4 0
2 years ago
Read 2 more answers
Solve the following: - 3 raised to 1 by 5 the whole raised to 4 (3^1/5)^4
Diano4ka-milaya [45]

Answer:

8.30256

Step-by-step explanation:

Step 1: Write out expression

((-3)^{\frac{1}{5} })^{4(3^{\frac{1}{5} })^4

Step 2: Use BPEMDAS to evaluate

(-1.24573)^{4(3^{\frac{1}{5} })^4

(-1.24573)^{4(1.24573)^4

(-1.24573)^{4(2.40822)

(-1.24573)^{9.6329}

= 8.30256

And we have our answer!

8 0
3 years ago
Introduction to complex numbers 5VV
sesenic [268]

Step-by-step explanation:

sqrt(-4) = sqrt(4×-1) = sqrt(4)×sqrt(-1) = 2i

6 0
1 year ago
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