Answer:
365.25 days
Step-by-step explanation:
Answer:
Step-by-step explanation:i solve is A△B=(A∪B)∖(B∩A)=(A∪B)∩(B∩A)c=(A∪B)∩(Bc∪Ac)=(B∪A)∩(Ac∪Bc)=(B∪A)∩(A∩B)c=(B∪A)∖(A∩B)=B△A
So first use long divsion and dived 135 by 5 and make that many groups containg 5 or the other way around as you are distributing the prouduct
Answer:
Option A. Line segment A
Step-by-step explanation:
we know that
The height of the triangle must be perpendicular to the base of the triangle
so
In this problem
The segment A is perpendicular to the given height
therefore
The base is the line segment A
let's take a peek at the graph.
the graph of the equation touches the x-axis at 1, 2 and 3, at 1 it crosses it, at 2 it crosses it, at 3 is doesn't cross it, it simply bounces off of it.
on the roots/solutions the graph crosses the x-axis, they have ODD multiplicity, on the solutions it bounces off of it, they have EVEN multiplicity, so then.
x = 1 => x - 1 = 0 <------ one factor
x = 2 => x - 2 = 0 <------ another factor
x = 3 => x - 3 = 0 <------ another factor, BUT with even multiplicity
(x-1)¹(x-2)¹(x-3)² = f(x)
(x-1)(x-2)(x-3)² = f(x).