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3 years ago

12

Find the midpoint of the segment whose endpoints are (8,6) and (-2,-8).

1 answer:

inna [77]3 years ago

5 0

Answer:

$\huge{ \fbox{ \sf{ \: ( \: 3 \: , \: - 1 \: )}}}$

Step-by-step explanation:

$\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}$

$\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and \: B(-2,-8) \: be \: (x2 \:, y2)}}$

$\underline{ \sf{Finding \: the \: midpoint}}$

$\boxed{ \rm{Midpoint \: = \: ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{8 + ( - 2)}{2} \: , \: \frac{6 + ( - 8)}{2} )}}$

$\mapsto { \sf{Midpoint = ( \frac{8 - 2}{2} \: , \: \frac{6 - 8}{2} }})$

$\mapsto{ \sf{Midpoint = ( \frac{6}{2} \: , \: \frac{ - 2}{2}) }}$

$\mapsto{ \sf{Midpoint = (3 \: \: , - 1)}}$

Hope I helped!

Best wishes!! :D

~ $\sf{TheAnimeGirl}$

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Use the periodic compound interest formula to solve.

77julia77 [94]

Answer:

$15,539.67

Step-by-step explanation:

Compound Interest Formula

$\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}$

where:

A = final amount
P = principal amount
r = interest rate (in decimal form)
n = number of times interest applied per time period
t = number of time periods elapsed

Given:

P = $11,000
r = 5.8% = 0.058
n = 4 (quarterly)
t = 6 years

Substitute the given values into the formula and solve for A:

$\implies \sf A=11000\left(1+\frac{0.058}{4}\right)^{(4 \times 6)}$

$\implies \sf A=11000(1.0145)^{24}$

$\implies \sf A=15539.67451...$

Therefore, the value of the investment after 6 years will be $15,539.67 to the nearest cent.

3 0

2 years ago

Which fraction has a repeating decimal as its decimal expansion?<br> w<br> w<br> w<br> cow

ArbitrLikvidat [17]

Answer:

w

Step-by-step explanation:

idk whats cow but w over co

8 0

3 years ago

The expression 60(0.75)^x represents the amount of a drug in milligrams that remains in the bloodstream after x hour. What was t

kogti [31]

It would be 60.

a(b)^x
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3 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

3 years ago

The formula for the circumference of a circle is C=2 nr. What is the radius of a circle with a

Vladimir [108]

Answer:

The formula for the circumference of a circle is C = 2πr, where r is the radius and C is the circumference. The equation solved for r is r =c/2π .

Step-by-step explanation: hope this helped!

8 0

3 years ago

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