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3 years ago

Someone help me please

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

7 0

Favourite starts fifth letter down farthest left column

Still working on the others

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2 years ago

One number is 1 more than 7 times the other number. If their sum is 73 more than

kvv77 [185]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\bf The \ two \ numbers \ are \ 12 \& \ 85 . }}}$

<h3>Step-by-step explanation:</h3>

Given that , One number is 1 more than 7 times the other number. If their sum is 73 more than

twice the smaller number. And we need to find the numbers. So let us take the

First Number be x .
Second number be 7x+1 .

$\underline{\red{\boldsymbol{ According \ to \ the \ Question :- }}}$

$\bf\implies 2( Small \ no.) + 73 = Bigger \ no. + Smaller \ no.\\\\\bf\implies 2x + 73 = x + 7x + 1\\\\\bf\implies 2x + 73 = 8x + 1 \\\\\bf\implies 8x - 2x = 73-1 \\\\\bf\implies 6x = 72 \\\\\bf\implies x =\dfrac{72}{6} \\\\\bf\implies \boxed{\red{\bf x = 12 }}$

Hence the smaller number is 12 and the bigger number will be :-

$\bf \implies Number_{bigger} = 7x + 1 \\\\\bf\implies Number_{bigger} =7(12)+1\\\\\bf\implies Number_{bigger} = 84 + 1 \\\\\bf\implies \boxed{\red{\bf Number_{bigger}=85 }}$

<h3>Hence the bigger number is 85 and the smaller number is 12. </h3>

5 0

2 years ago

Read 2 more answers

Someone help me please​

Someone help me please