(X-10)(X-10)
You need to first multiply out the brackets. So, first times X by X, which makes x^2 . Then do -10 x -10 which makes 100. You then need to multiply the X within the first bracket with the minus 10 in the second bracket which makes -10x. Do the same but with the -10 from the first bracket and the X from the second which again makes -10x. So altogether you have x^2-10x-10x+100. This can be simplified down to x^2-20x+100. You then do the same thing for the second question :)
Answer:
Denote the center of circle as O, the 2 endpoints of shaded segment as AB, then we have:
section OAB area = pi x radius^2 x (120/360) = pi x 6^2 x (1/3) = 37.7 (cm2)
Considering triangle OAB, we have OA = OB = radius, angle AOB = 120 deg. Denote OH as the height of triangle. H lies on AB.
=> Applying cosine and sine theorem in right triangle AHO:
OH = OA x cos 60 = 6 x (1/2) = 3 (cm)
AH = OA x sin 60 = 6 x (sqrt3)/2 = 5.2 (cm)
=> triangle AOB area:
A = triangle AOH area x 2
= AH x OH x (1/2) x 2 = 3 x 5.2 x (1/2) x 2 = 15.6 (cm2)
=> shaded segment area = section OAB area - triangle AOB
= 37.7 - 15.6 = ~21.1 (cm2)
Hope this helps!
:)
Answer:
<h2>Let's call

the number of dollars Paul owers.</h2>
Notice that the word "minus" refers to a difference.
So, basically, we just need to subtract 18 from the variable as follows

Therefore, the expression which represents the number of dollars Paul owes minus 18 is 
1*(2+3+2)+2*3
1*7+6
7+6
13 ft^2