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Stolb23 [73]
3 years ago
8

Identify the domain and range

Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0
1. First one (if i’m not mistaken) and SoMeTiMeS I dOnT wAnNa bE hApPy
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Question 6
Otrada [13]

Answer:

d is the answer

Step-by-step explanation:

29+11+22=33+29=62 or 29+11=40+22=62

5 0
2 years ago
Plese help me fast I will mark you brainlist​
Alona [7]

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x= 70 y= 70

Step-by-step explanation:

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3 years ago
Paul has 183 stamps his friends gave 15 stamps for his birthday how many stamps does Paul have after he received stamps from his
ehidna [41]

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198.

Step-by-step explanation:

183+15=198

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3 years ago
Read 2 more answers
A teepee is designed to have a diameter of 10 ft and a volume of 366ft³ what is the height? A.15ft , b.14 ft, c 5ft, or 1 ft
Katarina [22]

Answer:

B.  14 ft approx

Step-by-step explanation:

Given data

A teepee  has a conical shape

Diameter= 10ft

radius= 5 ft

Volume = 366ft³

Height = ????

The expression for the volume is

V= 1/3πr^2 h

substitute

366= 1/3*3.142*5^2*h

366= 1/3*78.55*h

366= 26.18h

h= 366/26.18

h=13.98 ft

h= 14 ft approx

Hence the Height is 14 ft approx

5 0
3 years ago
Read 2 more answers
An article describes the chemical compositions of certain minerals in the early Archaean mantle. For a certain type of olivine a
Ket [755]

Answer:

The mean is 40.35 and the standard deviation is 0.13.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a certain type of olivine assembly, the silicon dioxide (SiO2) content (in weight percent) in a randomly chosen rock has mean 40.35 and standard deviation 0.4.

Sample of 10:

By the Central Limit Theorem, the mean is 40.35, and the standard deviation is s = \frac{\sigma}{\sqrt{n}} = \frac{0.4}{\sqrt{10}} = 0.13

The mean is 40.35 and the standard deviation is 0.13.

5 0
3 years ago
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