Is it possible capture the correlation between continuous and categorical variable?

1 answer:

7 0

It is possible to<span> capture the correlation (or lack thereof) between continuous and categorical variable using Analysis of Covariance (</span>ANCOVA) technique to capture association among continuous and categorical variables.

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Q1.Simplify:

solniwko [45]

$\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\$

$\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\$

$\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625$

6 0

2 years ago

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Please help I’ll give Brainly

Charra [1.4K]

Answer:

The last choice

Step-by-step explanation:

5^2 + 12^2 = 13^2

25 + 144 = 169

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2 years ago

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If you spend $448.37 on a car each month, what is your new subtotal of take-home pay after expenses? $480.29 $629.75 $779.21 $92

Black_prince [1.1K]

I just had the question and the answer is $629.75

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3 years ago

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Find the mid point of p(3,5) and q-2,13

Vsevolod [243]

Answer:

(0.5, 9 )

Step-by-step explanation:

Using the midpoint formula

[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

with (x₁, y₁ ( = (3, 5) and (x₂, y₂ ) = ( - 2, 13 )

midpoint = [0.5(3 - 2), 0.5(5 + 13) ] = [0.5(1), 0.5(18) ] = (0.5, 9 )

3 0

3 years ago

Help me in this question

KATRIN_1 [288]

H = -5t^2 +5t + 10

a) t = 0, h = 10 at time 0

b) h = (-5t + 10) ( t + 1)

c) put 0 in for the height and set each factor = to 0 and solve each
0 = (-5t + 10) and 0 = (t + 1)
solve each t = 2 and t = -1, so t = 2 sec is your solution

d) because a parabola is symmetric, the max will be half way between -1 and 2, at t = 1/2

h = -5(1/2)^2 +5(1/2) + 10
h = -5(1/4) + 5/2 +10
h = -5/4 + 5/2 + 10
h = -5/4 + 10/4 + 40/4
h = 45/4

5 0

3 years ago