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3 years ago

This element is found in a group 11 and has a mass of 107.87 ?

Mathematics

1 answer:

Valentin [98]3 years ago

3 0

Answer:

(Ag) Silver is located in group 11 with mass of 107.87.

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1 1/4 x 3 5/6 need helppp

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Answer:

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Step-by-step explanation:

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List two ways a rectangle and a square are alike

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Rectangles and squares are alike in that both have two pairs of parallel sides and four right angles.

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3 years ago

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Which of the following is the standard equation of the ellipse with vertices at (1,0) and (27,0) and an eccentricity of 5/13?

Dovator [93]

The equation of the elipse is given by:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

The equation of an elipse of center $(x_0, y_0)$ is given by:

$\frac{(x - x_0)^2}{a^2} + \frac{(y - y_0)^2}{b^2} = 0$

Values a and b are found according to the vertices and the eccentricity.

It has vertices at (1,0) and (27,0), thus:

$x_0 = \frac{27 + 1}{2} = 14$

$y_0 = \frac{0 + 0}{2} = 0$

$a = \frac{27 - 1}{2} = 13$

$a^2 = 169$

It has eccentricity of $\frac{5}{13}$ , thus:

$\frac{5}{13} = \frac{c}{a}$

$\frac{5}{13} = \frac{c}{13}$

$c = 13$

Thus, b is given according to the following equation:

$c^2 = a^2 - b^2$

$b^2 = a^2 - c^2$

$b^2 = 169 - 25$

$b = \sqrt{144}$

$b = 12$

The equation of the elipse is:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

A similar problem is given at brainly.com/question/21405803

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3 years ago

(WILL MARK BRAINLIEST) Solve x^2-4x-12=0. SHOW YOUR WORK! show and DESCRIBE EACH STEP!

Natasha_Volkova [10]

x^2 - 4x - 12 = 0
factors
(x - 6)(x + 2) = 0
Set (x - 6) and (x + 2) equal to 0 and solve for xx.
x - 6 = 0; x = 6
x + 2 = 0; x = -2

answer
x = -2 or x = 6

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3 years ago

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What is the area of the triangle? 13 5 12

andrey2020 [161]

Answer:29

Step-by-step explanation:

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3 years ago

This element is found in a group 11 and has a mass of 107.87 ? ​

This element is found in a group 11 and has a mass of 107.87 ?