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Neko [114]
1 year ago
9

6x + -2y² + 4xy² + 3x² + 5xy² simplify it​

Mathematics
2 answers:
r-ruslan [8.4K]1 year ago
7 0

\large\displaystyle\text{$\begin{gathered}\sf 6x+-2y^{2}+4xy^{2}+3x^{2} +5xy^{2}    \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Group\:like\:terms \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf =3x^2+6x-2y^2+4xy^2+5xy^2 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Sum\:similar\:elements:\:4xy^2+5xy^2=9xy^2 \end{gathered}$}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf 3x^2+6x-2y^2+9xy^2 \end{gathered}$} }

Nookie1986 [14]1 year ago
4 0
Answer: 6x+-2y^2+9xy^2+3x^2
Explanation: using like-combine terms I combined the number with the same variables like 4xy^2 and 5xy^2. Then kept the ones that I can’t combine and let them be.
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Step-by-step explanation:

Hey there!

Given;

8 =  \frac{p}{7}

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Therefore the value of "p" is 56.

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spayn [35]

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Step-by-step explanation:

Let the original retail price be 'x'

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