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Mrrafil [7]
3 years ago
12

Solutes in the bloodstream enter cells through osmosis, which is the diffusion of fluid through a semipermeable membrane. Let C

= C(t) be the concentration of a certain solute inside a particular cell. The rate at which the concentration inside the cell is changing is proportional to the difference in the concentration of the solute in the bloodstream and the concentration within the cell. Let k be the constant of proportionality. Suppose the concentration of a solute in the bloodstream is maintained at a constant level of L gm/cubic cm. Find the differential equation that best models this situation. (Use C for the concentration within the cell, not C(t).)
Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

since the rate at  which concentration inside the cell is proportional to the difference in the concentration of the solute in the blood stream and the concentration within the cell, then the rate of change of concentration within the cell is equals to K(L-C).

Thus, the  required differential equation is Δc/Δt = K( L - C ).

Step-by-step explanation:

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kati45 [8]

Slope: 1/5

Y-intercept: 0

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3 years ago
48a2 + 32a2 + 16a by 4a?
lbvjy [14]

(48a^3 + 32a^2 + 16a) / 4a = ?

48a^3 / 4a = 12a^2

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(48a^3 + 32a^2 + 16a) / 4a = 12a^2 + 8a + 4

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7 0
2 years ago
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Need help badly don’t have answer to this problem.
NikAS [45]
There are a couple of ways to tackle this one, using the 45-45-90 rule or just using the pythagorean theore, let's use the pythagorean theorem.

the angle at A is 45°, and its opposite side is BC, the angle at C is 45° as well, and its opposite side is AB, well, the angles are the same, thus BC = AB.

hmmm le'ts call hmmm ohh hmmm say z, thus BC = AB = z.

\bf \textit{using the pythagorean theorem}
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c^2=a^2+b^2 \implies (6\sqrt{2})^2=z^2+z^2
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4 0
3 years ago
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PLEASE HELP!
Orlov [11]
We have that
<span>If (5x-4+13x=5) -------------->  then x=1/2
Step 1
</span>let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
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3 0
3 years ago
Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

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Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

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3 years ago
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