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Leokris [45]
2 years ago
6

Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12

, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper. She does not want to list all of the ages, so should she use the range (difference between the highest and lowest values) or a measure of central tendency (mean, median) to describe them? Justify your choice.
Mathematics
1 answer:
BARSIC [14]2 years ago
7 0

We are told that Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper.

Since we know that range of a data is difference between the highest and lowest values of a data set. Range of our data set will be 4 (14-10). A group of different ages could have same range as Christina's data set. So range will be not a good option.

A measure of central tendencies will be better option to represent information about ages of softball team players. Mean will give the average age of softball players.

\text{Mean age of players}=\frac{10+11+11+12+12+12+12+12+13+13+13+14}{12}

\text{Mean age of players}=\frac{145}{12}=12.0833

Let us find median of data.

10,11,11,12,12,12,12,12,13,13,13,14        

\text{Median age of softball players}=\frac{12+12}{2}

\text{Median age of softball players}=\frac{24}{2}=12

We can see that average of our data is 12 years.    

Therefore, a measure of central tendency will be better choice to describe ages of softball players.      

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yuradex [85]

Answer: There are 400 tadpoles in the year 1994.

This is because any point is of the form (x,y) where in this case

x = year number

y = tadpole population number

So (x,y) = (1994, 400) means x = 1994 and y = 400 pair up together.

In short, the year x = 1994 corresponds to the population of y = 400 tadpoles.

From the years 1990 to 1992, the population is increasing since the curve goes upward when moving from left to right. Then from 1992 to 1993, the population decreases hitting its lowest point in that specific region. From 1993 to 1997, the population increases before it decreases again from 1997 to 1999.

5 0
3 years ago
Please write down your work on the loose leaf, take a CLEAR picture, and upload here. Thank you.
Zigmanuir [339]

Answer:

m(∠C) = 18°

Step-by-step explanation:

From the picture attached,

m(arc BD) = 20°

m(arc DE) = 104°

Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.

m(∠C) = \frac{1}{2}[\text{arc(EA)}-\text{arc(BD)}]

Since, AB is a diameter,

m(arc BD) + m(arc DE) + m(arc EA) = 180°

20° + 104° + m(arc EA) = 180°

124° + m(arc EA) = 180°

m(arc EA) = 56°

Therefore, m(∠C) = \frac{1}{2}(56^{\circ}-20^{\circ})

m(∠C) = 18°

8 0
3 years ago
When y = 35,x = 2.5. If the value of y varies directly with x what is the value of y when the value of xis 3.25
leonid [27]

Answer:

The value of y would be 45.5

Step-by-step explanation:

To solve this problem, start with the base form of direct variation.

y = kx

Now we can use our original values to model the equation and find k.

35 = k(2.5)

14 = k

Now we can model the equation as:

y = 14x

Now to find y, when x = 3.25, simply put 3.25 into the equation.

y = 14(3.25)

y = 45.5

8 0
3 years ago
the cost of running an appliance varies jointly as the number of watts used, the hours of operation, and the cost per kilo-watt
zhuklara [117]
Suppose:
C=cost
c=cost per kilo-watt hour
w=number of watts
h=number of hours
thus
C=kwhc
where:
k=constant of proportionality:
k=C/(whc)
but
C=15 when w=6000, h=10/60=1/6 hours, c=7.5 cents per kw/h
thus
k=15/(6000*1/6*7.5)
k=0.002
thus:
C=0.002(whc)
hence:
when 
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C=0.002(6000*70/3*7.5)
C=2100 cents
C=$21

7 0
3 years ago
Solve the inequality 6t>t+6. Enter your answer as an inequality with just t on the left side. For example, if the inequality
ahrayia [7]

Answer:  t > 6/5

In decimal form, this would be t > 1.2

==============================================

Work Shown:

6t > t+6

6t-t > t+6-t ...... subtracting t from both sides

5t > 6

5t/5 > 6/5 .... dividing both sides by 5

t > 6/5

t > 1.2

3 0
3 years ago
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