We are told that Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper.
Since we know that range of a data is difference between the highest and lowest values of a data set. Range of our data set will be 4 (14-10). A group of different ages could have same range as Christina's data set. So range will be not a good option.
A measure of central tendencies will be better option to represent information about ages of softball team players. Mean will give the average age of softball players.
Let us find median of data.
10,11,11,12,12,12,12,12,13,13,13,14
We can see that average of our data is 12 years.
Therefore, a measure of central tendency will be better choice to describe ages of softball players.
Answer:
Mean is 83.7%
And, the standard deviation is 0.033
Step-by-step explanation:
The computation of the mean and the standard deviation is as follows:
Let us assume the P be the sample proportion
Mean is 83.7%
And, the standard deviation is
= 0.033
Answer:
Hence, the total cost of mailing 10 ounces is:
$ 2.52
Step-by-step explanation:
If postage costs $.54 for the first ounce and $.22 for the each additional ounce.
i.e. cost of first ounce=$ 0.54.
Now let x denote the number of ounces after the first ounce,
Hence, the cost of x ounces=$ (0.22×x)=$ 0.22 x
Hence, the cost of mailing (x+1) ounces is: $ (0.54+0.22 x)
Now, we have to find the cost of mailing a 10- ounce envelope.
i.e. after the first ounce we need 9 more ounces.
Hence, the total cost of mailing is calculated as:
Hence, cost of mailing 10 ounces is:
$ 2.52