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Leokris [45]
3 years ago
6

Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12

, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper. She does not want to list all of the ages, so should she use the range (difference between the highest and lowest values) or a measure of central tendency (mean, median) to describe them? Justify your choice.
Mathematics
1 answer:
BARSIC [14]3 years ago
7 0

We are told that Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper.

Since we know that range of a data is difference between the highest and lowest values of a data set. Range of our data set will be 4 (14-10). A group of different ages could have same range as Christina's data set. So range will be not a good option.

A measure of central tendencies will be better option to represent information about ages of softball team players. Mean will give the average age of softball players.

\text{Mean age of players}=\frac{10+11+11+12+12+12+12+12+13+13+13+14}{12}

\text{Mean age of players}=\frac{145}{12}=12.0833

Let us find median of data.

10,11,11,12,12,12,12,12,13,13,13,14        

\text{Median age of softball players}=\frac{12+12}{2}

\text{Median age of softball players}=\frac{24}{2}=12

We can see that average of our data is 12 years.    

Therefore, a measure of central tendency will be better choice to describe ages of softball players.      

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According to the given information:

1) There are a total of 10 slips after adding.

8 slip with 3 on it

2 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

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2 )No of total slips after addition = 12

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3 n = 18

n = 6

4 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

expectation value = probability of 3 x 3 + probability of 9 x 9

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 8

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Minimum of 38 has to be added .

To know more about Probability visit:

brainly.com/question/17487084

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I understand that the question you are looking for is:

1:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add one additional $9$ to the bag? 2:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add two additional $9$'s (instead of just one) to the bag? 3:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do we have to add to make the expected value equal to $6$? 4:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do I have to add before the expected value is at least $8$?

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