<u>Answer:</u>
is an inorganic compound.
<u>Solution:</u>
- Firstly, all the known definitions of organic compounds excludes Carbonic acid and it's salt from organic compounds except if 'C' is present in the cation.
- Secondly, Sodium is a metal which organic compounds cannot posses as a compound.
- Lastly, there is absence of C-H bond which is present in all the organic compounds.
Hence, we can conclude that
is an inorganic compound though there is presence of Carbon atom in it.
Answer: c. Transition Reaction
Explanation:
During the transition reaction, Acetyl-CoA is formed and connects the first stage of glycolysis with the Krebs Cycle (Citric Acid Cycle). In the presence of oxygen, pyruvate enters the mitochondria and is oxidized to form a compound of 2 carbon, acetate, with energy and CO2 release. During this process, the acetate binds to a coenzyme(coenzyme A (CoA)) - forming the acetyl-coenzyme A.
The 3 steps:
1. pyruvate is oxidized and forms acetate with liberation of CO2;
2. the energy released in the oxidation of pyruvate is stored in the reduction reaction of NAD+ to NADH + H+
3. The acetate molecule combines with coenzyme A to form acetyl-coenzyme A.
Answer:
Goats are more profitable than sheep. There are many factors that contribute to a farmer's profits. These factors include the price that goats or sheep sell for at market. ... Lastly, goats and sheep both produce multiple products that can be marketed including wool, milk, and meat.
Explanation:
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂