The width of a rectangle is 16 cm less than the length the perimeter is 98 cm find the rectangles dimensions

1 answer:

8 0

So width is l-16, l being the length. perimeter is 2w+2l=98. substitute w for l-16 for 2(l-16)+2l=98. Now, distribute to get 2l-32+2l=98. Add 32 to both sides for 2l+2l=130. then, 4l=130. divide both sides by four, so the length is 32.5. plug this into the original perimeter equation for 2w+2(32.5)=98. Again, distribute and subtract so your equation is 2w=33. Divide both sides by 2 so your width is 16.5
so width is 16.5 cm, and length is 32.5 cm
hope this helps!

You might be interested in

Use the Law of Syllogism to form a new conditional statement that follows from the pair of true statements.If she makes an A on

aleksandrvk [35]

Answer:

cffffffffffffffklhvoith

Step-by-step explanation:

cicvb gifhbgoibjtiod

3 0

2 years ago

Find the arc length intercepted by a central angle of radians in a circle whose radius is 18.4 inches. 13.8π 15.2π 24.5π

Margarita [4]

If the measure of the given central angle is $\theta$ rad, then the length of the subtended arc is $\ell$ satisfying

$\dfrac{\ell}{2\pi(18.4\,\mathrm{in})}=\dfrac{\theta\,\mathrm{rad}}{2\pi\,\mathrm{rad}}\implies\ell=36.8\pi\theta\,\mathrm{in}$

It's not clear from the question what the value of $\theta$ is...

7 0

3 years ago

Read 2 more answers

What is three quarters of £42 and a quarter of £42

maksim [4K]

$three \ quarters \to \frac{3}{4} \\\\ \frac{3}{4} \ of \ 42\£ = \\\\ =\frac{3}{4}*42\£= \\\\ =\frac{3}{2}*21\£= \\\\ =\frac{63\£}{2} = \\\\= \boxed{31.5\£} \\\\\\\ a \ quarter \to \frac{1}{4} \\\\ \frac{1}{4} \ of \ 42\£= \\\\ =\frac{1}{4}*42\£= \\\\ =\frac{21\£}{2}= \\\\ =\boxed{10.5\£}$