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3 years ago

Determine whether (6,4) is a solution to the following system of linear equations: x + y=10.....x-y=-2*

Mathematics

1 answer:

nevsk [136]3 years ago

4 0

For this case we have the following system of two equations with two unknowns:

$x + y = 10\\x-y = -2$

We want to know if the point $(x, y) = (6,4)$ is the solution of the system:

We replace:

$6 + 4 = 10$ , meets the first equation.

$6-4 = 2,$ does not comply with the second equation.

Therefore, it is not system solution.

Answer:

The point is not system solution

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3 years ago

Solve for x: √(32^0 + 2/3)=(0.6)^2-3x

malfutka [58]

Step-by-step explanation:

<u>Given</u>: √{32⁰ + (2/3)} = (0.6)²⁻³ˣ

<u>Asked</u>: Find the value of x = ?

<u>Solution:</u> Given that √{32⁰ + (2/3)} = (0.6)²⁻³ˣ

⇛√{1 + (2/3)} = (0.6)²⁻³ˣ

⇛√{(1/1) + (2/3) = (0.6)²⁻³ˣ

⇛√{(1*3 + 2*1)/3} = (0.6)²⁻³ˣ

⇛√{(3 + 2)/3} = (0.6)²⁻³ˣ

⇛√(5/3) = (0.6)²⁻³ˣ

Squaring on both sides then

⇛{√(5/3)}² = {(0.6)²⁻³ˣ}²

⇛√(5²/3²) = {0.6}(²⁻³ˣ)²

⇛√{(5*5)/(3*3)} = {0.6}(²⁻³ˣ)²

⇛5/3 = {0.6}(²⁻³ˣ)²

[ $\mathsf{\because}$ (aᵐ)ⁿ = aᵐⁿ]

⇛5/3 = (0.6)²*²⁻³ˣ*²

⇛5/3 = (0.6)⁴⁻⁶ˣ

⇛5/3 = (6/10)⁴⁻⁶ˣ

⇛5/3 = {(6÷2)/(10÷2)})⁴⁻⁶ˣ

⇛5/3 = (3/5)⁴⁻⁶ˣ

⇛(3/5))⁻¹ = (3/5)⁴⁻⁶ˣ

[ $\mathsf{\because}$ a⁻ⁿ = 1/aⁿ]

Base are the same, so the exponents must be equal.

$\mathsf{\therefore}$ -1 = 4 - 6x

Shift the number 4 from RHS to LHS, changing it's sign.

⇛-1 - 4 = -6x

⇛-5 = -6x

⇛x = {(-5)/(-6)}

$\mathsf{\therefore}$ x = 5/6

<u>Answer</u><u>:</u> Hence, the value of x for the given problem is 5/6.

<u>also </u><u>read </u><u>similar </u><u>questions</u><u>:</u> (1/3)^-2 + (1/4)^-2 = (125)^x Find the value of x? brainly.com/question/25746379?referrer

(3^-2 × 4^-2)^-3 = 12^x In the given expression find the value of x. brainly.com/question/25746273?referrer

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