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3 years ago

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Determine whether (6,4) is a solution to the following system of linear equations: x + y=10.....x-y=-2*

1 answer:

nevsk [136]3 years ago

4 0

For this case we have the following system of two equations with two unknowns:

$x + y = 10\\x-y = -2$

We want to know if the point $(x, y) = (6,4)$ is the solution of the system:

We replace:

$6 + 4 = 10$ , meets the first equation.

$6-4 = 2,$ does not comply with the second equation.

Therefore, it is not system solution.

Answer:

The point is not system solution

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*) Simplify the second expression<br> 2(2m + 2) + m.<br> 2(2m + 2) + m =<br> m +<br> ?

olga55 [171]

Answer:

5m + 4

Step-by-step explanation:

First, use the distributive property to open the parentheses.

2(2m + 2) + m = _m + 4

4m + 4 + m = _m + 4

Simplifiy:

5m + 4

Hope this helps!

4 0

3 years ago

Read 2 more answers

I need answer and specific explanation plz...

vitfil [10]

Answer:

The smallest model - bottom right - in the question diagram represents $\sqrt[3]{64}=4$ .

Step-by-step explanation:

Considering the radical expression

$\sqrt[3]{64}$

Lets simply this radical expression first

As

$\sqrt[3]{64}$

$\mathrm{Factor\:the\:number:\:}\:64=4^3$

$=\sqrt[3]{4^3}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a,\:\quad \:a\ge 0$

$\sqrt[3]{4^3}=4$

$=4$

Therefore, $\sqrt[3]{64}=4$

Now, as we can determine that $\sqrt[3]{64}=4$ . So, the smallest model in the question diagram represents $\sqrt[3]{64}=4$ as each face of the cube of the smallest model in the diagram - bottom right - has 4 squares.

Therefore, the smallest model - bottom right - in the question diagram represents $\sqrt[3]{64}=4$ .

Keywords: square cube root, radical expression

Learn more about radical expression from brainly.com/question/13984232

#learnwithBrainly

7 0

3 years ago

Graph a parabola whose x-intercepts are at x=-3 and x=5 and whose minimum value is y=-4

docker41 [41]

Answer:

(See explanation for further details)

Step-by-step explanation:

The standard equation of the parabola is:

$y + 4 = C \cdot (x-k)^{2}$

The formula is now expanded into a the form of a second-order polynomial:

$y + 4 = C\cdot x^{2} -2\cdot C\cdot k \cdot x +C\cdot k^{2}$

$y = C\cdot x^{2} - (2\cdot C \cdot k) \cdot x + (C\cdot k^{2}-4)$

The general equation of the second-order polynomial is:

$x = \frac{2\cdot C \cdot k \pm \sqrt{4\cdot C^{2}\cdot k^{2}-4\cdot C\cdot (C\cdot k^{2}-4)}}{2\cdot C}$

$x = k \pm \frac{\sqrt{C^{2}\cdot k^{2}-C^{2}\cdot k^{2}+4\cdot C}}{C}$

$x = k \pm 2\cdot \frac{\sqrt{C}}{C}$

$x = k \pm \frac{2}{\sqrt{C}}$

The equations to be solved are presented herein:

$-3 = k -\frac{2}{\sqrt{C}}$

$5 = k + \frac{2}{\sqrt{C}}$

Now, the solution of the system is:

$-3 +\frac{2}{\sqrt{C}} = 5 -\frac{2}{\sqrt{C}}$

$\frac{4}{\sqrt{C}} = 8$

$\sqrt{C} = \frac{1}{2}$

$C = \frac{1}{4}$

$k = 5 - \frac{2}{\sqrt{\frac{1}{4} }}$

$k = 1$

The equation of the parabola is:

$y = \frac{1}{4}\cdot (x-1)^{2} -4$

Lastly, the graphic of the function is included as attachment.

3 0

3 years ago

Evaluate the expression

kifflom [539]

Answer:-64

Step-by-step explanation:

256 multiplied by 1/4 then make it negative

5 0

3 years ago

Read 2 more answers

2+12×2=<br>31/2020 123 PM

tia_tia [17]

Answer:

$26$

Step-by-step explanation:

1) first, Simplify 12 × 2 to 24.

$2 + 24$

2) then, Simplify 2 + 24 to 26.

$26$

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>26</u></em><em><u>.</u></em>

8 0

3 years ago

Read 2 more answers