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ra1l [238]
3 years ago
6

A+sports+broadcaster+predicts+a+basketball+team+will+score+88+points+in+the+next+game.Of+the+team+actually+scored+98+points+,+wh

at+was+rhe+broadcasters+percent+error?+round+your+answer+to+the+nearest+tenth+of+a+percent&spell=1&sa=X&ved=2ahUKEwj7xZ_AtfPrAhUbHM0KHRHwCQgQkeECKAB6BAgJEAI&biw=375&bih=626
Mathematics
1 answer:
wolverine [178]3 years ago
5 0

Answer:

10.2%

Step-by-step explanation:

Prediction of the broadcaster = 88 points

Actual score scored = 98points

% error = actual score-predicted score/actual score × 100℅

Substitute the given scores into the formula;

%error = 98-88/98 × 100

%error = 10/98 × 100

%error = 1000/98

%error = 10.2%

Hence the broadcaster percentage error is approximately 10.2%

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1. A system of linear equations that has one solution has slopes that are__________
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different

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different slopes gives one solution

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8 0
3 years ago
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3. From the table below, find Prof. Xin expected value of lateness. (5 points) Lateness P(Lateness) On Time 4/5 1 Hour Late 1/10
wariber [46]

Answer:

The expected value of lateness \frac{7}{20} hours.

Step-by-step explanation:

The probability distribution of lateness is as follows:

  Lateness             P (Lateness)

  On Time                     4/5

1 Hour Late                  1/10

2 Hours Late                1/20

3 Hours Late                1/20​

The formula of expected value of a random variable is:

E(X)=\sum x\cdot P(X=x)

Compute the expected value of lateness as follows:

E(X)=\sum x\cdot P(X=x)

         =(0\times \frac{4}{5})+(1\times \frac{1}{10})+(2\times \frac{1}{20})+(3\times \frac{1}{20})\\\\=0+\frac{1}{10}+\frac{1}{10}+\frac{3}{20}\\\\=\frac{2+2+3}{20}\\\\=\frac{7}{20}

Thus, the expected value of lateness \frac{7}{20} hours.

8 0
3 years ago
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