Question

The parallelogram PQRS has vertices P (-2, 3), Q (1, 4), R (2, 6) and S (- 1, 5). Find the coordinates of the point of intersection of the diagonals.

Answer 1

Call the intersection of 2 diagonal lines as I(a;b)
=> I is the midpoint of the diagonal PR
<=> a= (-2+2)/2. And. b=(3+6)/2
<=> a=0. And. b= 9/2
=> I(0;9/2)