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Karo-lina-s [1.5K]
3 years ago
8

2 v What is the equation of a line that is parallel to y = -4x – 3 and shifted down 3 units?

Mathematics
1 answer:
Ugo [173]3 years ago
3 0

Answer: y=-4x-6

Step-by-step explanation:

Given

The equation of line is y=-4x-3

The line which is parallel to the given line is y=-4x+c

and shifted by 3 units down i.e. its y-intercept is 3 units below the given line

\therefore y=-4x-3-3\\\Rightarrow y=-4x-6

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Answer: the rate of the jet in still air is 685 mph and the rate of the jetstream is 75 mph

Step-by-step explanation:

Let x represent the rate of the jet in still air.

Let y represent the rate of the jet jetstream.

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Flying against the jetstream, a jet travels 3050 miles in 5 hours. This means that the total speed of the jet would be (x - y) mph. Therefore,

3050 = 5(x - y)

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Flying with the jetstream, the same jet travels 3800 miles in 4 hours. This means that the total speed of the jet would be (x + y) mph. Therefore,

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2x = 1370

x = 1370/2 = 685mph

Substituting x = 685 into equation 1, it becomes

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y = 685 - 610 = 75mph

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