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2 years ago

Which table shows a proportional relationship between x and y

Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

Answer:

The answer is B (1 , 3) , (2 , 6) , (4 , 12) , (5 , 15)

Step-by-step explanation:

∵ X : 1 , 2 , 4 , 5

∵ Y : 3 , 6 , 12 , 15

∵ 2/6 = 1/3

∵ 4/12 = 1/3

∵ 5/15 = 1/3

∴ 1/3 = 2/6= 4/12 = 5/15 = 1/3 ⇒ all are proportion

∴ Answer B is in proportional relationship

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HELP ME!! im so stumped. will give brainliest!

Olegator [25]

Answer:

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

Now we need to find the x-intercepts of that parabola. So first we begin by finding the equation of parabola using vertex formula:

$y=a\left(x-h\right)^2+k$

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

$y=a\left(x-1\right)^2-9$ ...(i)

Plug given point (0, -6). into (i)

$-6=a\left(0-1\right)^2-9$

$-6=a\left(-1\right)^2-9$

$-6=a\left(1\right)-9$

$-6+9=a$

$3=a$

Plug a=3 into (i)

$y=3\left(x-1\right)^2-9$

Now to find x-intercept, we just plug y=0 and solve for x

$y=3\left(x-1\right)^2-9$

$0=3\left(x-1\right)^2-9$

$9=3\left(x-1\right)^2$

$3=\left(x-1\right)^2$

$\pm \sqrt{3}=x-1$

$1+\pm \sqrt{3}=x$

Hence final answer are

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2 years ago

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strojnjashka [21]

the answer is:

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hope this helps :)

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