The given condition is an arithmetic sequence with the first term (a1) is 1 penny and the common difference (d) is 1 penny. A year that is not a leap year has 365 days (n). The arithmetic series (S) is calculated through formula,
S = (n/2) (2a1 + (n - 1) x d)
Substituting the known values,
S = (365/2) (2 x 1 + (365 - 1) x 1)
S = 66795 pennies
A dollar is 100 pennies. Therefore, at the end of the year, the total savings is $667.95.
The answer is 440. What I do is just take the -11 and -15 out of the parentheses so it is -11*-15 and the answer is 165. Then, you take -11 and -25 out of the parentheses and find the answer. Add them together. Hope that helped :)
