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3 years ago

A month of the year is chosen at random. What is the probability that the month starts with the letter Jor the letter M?

Mathematics

2 answers:

tamaranim1 [39]3 years ago

4 0

Answer:

5 out of 12

5/12

January, March, May, June, July

There are three months whose name starts with the letter 'j': January, June, July

There are two months whose name starts with the letter 'm': March, May

So altogether, there are 5 months whose name starts with the letter 'j' or 'm'. So the possible outcome is 5 and total number of sample space is 12.

Therefore the required probability is: 5/12

PLEASE GIVE BRAINLYEST :)

andrew-mc [135]3 years ago

4 0

Answer:

Step-by-step explanation:

Total outcomes = 12

Letter starting with M = 2 (march & May)

Letter starting with J = 3 ( January, June, July)

P(letter starting with M and J)=2/12+3/12=5/12

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Find the value of the trig function indicated

Lera25 [3.4K]

Answer:

$\cos(\theta)=\frac{4}{5}$

Step-by-step explanation:

Step 1:

Let us find the missing side. We know this is a right triangle, so we can use the pythagorean thereom to find the last side. Let us set 12 as variable a, 20 as variable c, and the unknown side as variable b.

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We do know that a length can never be negative, so the side b would be 16.

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According to SOHCAHTOA, cosine is utilizes the adjacent and hypotenuse of the given angle theta. Let us write the equation:

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I hope this helps! Let me know if you have any questions :)

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