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Reptile [31]
3 years ago
5

A month of the year is chosen at random. What is the probability that the month starts with the letter Jor the letter M?

Mathematics
2 answers:
tamaranim1 [39]3 years ago
4 0

Answer:

5 out of 12

5/12

January, March, May, June, July

There are three months whose name starts with the letter 'j': January, June, July

There are two months whose name starts with the letter 'm': March, May

So altogether, there are 5 months whose name starts with the letter 'j' or 'm'. So the possible outcome is 5 and total number of sample space is 12.

Therefore the required probability is: 5/12

PLEASE GIVE BRAINLYEST :)

andrew-mc [135]3 years ago
4 0

Answer:

Step-by-step explanation:

Total outcomes = 12

Letter starting with M = 2 (march & May)

Letter starting with J = 3 ( January, June, July)

P(letter starting with M and J)=2/12+3/12=5/12

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<h2>☀️ <u>Solution</u><u>:</u></h2>

We all know that,

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⇛ Eyes of cows + Eyes of chickens = 162

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According to question(Cond.-1)

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Framing equation,

⇛ Feet of cows + Feet of chickens = 270

⇛ 4x + 2y = 270

⇛ 2(2x + y) = 270

⇛ 2x + y = 135 ----------(2)

Subtracting eq.(1) from eq.(2),

⇛ 2x + y - (x + y) = 135 - 81

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4 years ago
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