Answer:
The third quartile is 56.45
Step-by-step explanation:
The given parameters are;
The first quartile, Q₁ = 30.8
The median or second quartile, Q₂ = 48.5
The mean, 
= 42.0
Coefficient of skewness = -0.38
The Bowley's coefficient of skewness (SK) is given as follows;
Plugging in the values, we have;
Which gives;
-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5
11.704 - 0.38·Q₃ = Q₃ - 66.2
1.38·Q₃ = 11.704 + 66.2 = 77.904
Q₃ = 56.45
The third quartile = 56.45.
Y= -2x-8
if I helped, please give me brainliest
Answer:
4445.18 pulgadas cúbicas
Step-by-step explanation:
Paso 1
La fórmula para la circunferencia de una esfera = 2πr
Circunferencia de una esfera = 64 pulgadas
Por eso,
64 = 2πr
Por lo tanto, encontramos r
Dividir ambos lados por 2π
64 / 2π = 2πr / 2π
r = 10.185916358 pulgadas
Radio r = 10.2 pulgadas
Paso 2
Volumen de una esfera
= 4/3 × π × r³
r = 10.2 pulgadas
Por lo tanto, 4/3 × π × (10.2) ³
= 4445.18 pulgadas cúbicas
Por lo tanto, el volumen en pulgadas cúbicas de una esfera = 4445.18 pulgadas cúbicas
Not really ready. But will be! FYI that's not really a question.
Answer:
x = 50*e∧ -t/100
Step-by-step explanation:
We assume:
1.-That the volume of mixing is always constant 300 gallons
2.-The mixing is instantaneous
Δ(x)t = Amount in - Amount out
Amount = rate * concentration*Δt
Amount in = 3 gallons/ min * 0 = 0
Amount out = 3 gallons/min * x/ 300*Δt
Then
Δ(x)t/Δt = - 3*x/300 Δt⇒0 lim Δ(x)t/Δt = dx/dt
dx/dt = - x/100
dx/ x = - dt/100
A linear first degree differential equation
∫ dx/x = ∫ - dt/100
Ln x = - t/100 + C
initial conditions to determine C
t= 0 x = 50 pounds
Ln (50) = 0/100 * C
C = ln (50)
Then final solution is:
Ln x = - t/100 + Ln(50) or
e∧ Lnx = e ∧ ( -t/100 + Ln(50))
x = e∧ ( -t/100) * e∧Ln(50)
x = e∧ ( -t/100) * 50
x = 50*e∧ -t/100
