3 years ago

Solve x^5-4x^3 is less than or equal to 0

1 answer:

5 0

Solve for x over the real numbers:
x^3 (x^2 - 4) = 0

Split into two equations:
x^3 = 0 or x^2 - 4 = 0

Take cube roots of both sides:
x = 0 or x^2 - 4 = 0

Add 4 to both sides:
x = 0 or x^2 = 4

Take the square root of both sides:
Answer: x = 0 or x = 2 or x = -2

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10) The temperature recorded at 12 noon was 15°C above zero. If it decreases at the rateof 3°C per hour until midnight, at what

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Answer:

at 8 pm the temperature will be -9 degrees. and at midnight the temperature will be negitive twenty one(-21) degrees

Step-by-step explanation: