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3 years ago

11

Solve x^5-4x^3 is less than or equal to 0

1 answer:

Aleks04 [339]3 years ago

5 0

Solve for x over the real numbers:
x^3 (x^2 - 4) = 0

Split into two equations:
x^3 = 0 or x^2 - 4 = 0

Take cube roots of both sides:
x = 0 or x^2 - 4 = 0

Add 4 to both sides:
x = 0 or x^2 = 4

Take the square root of both sides:
Answer: x = 0 or x = 2 or x = -2

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