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3 years ago

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Genise has some savings. After babysitting, she adds $75 to her savings. How much money has Genise saved? Write an expression to

represent this situation.

1 answer:

Sedbober [7]3 years ago

8 0

Answer:

She saved 25

Step-by-step explanation:

75-50

25

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Considere a função de oferta como sendo y= 5x - 1/2 e a função de demanda como sendo y= -7x + 47/2 , onde x é a quantidade e y é

swat32

A) Temos que igualar isso a 2,50, que é o valor de y, ou seja, o valor do preço. Façamos isso, então, na função de demanda.

$y = -7x + \frac{47}{2}$

Substituir.

$2,50 = - 7x + \frac{47}{2}$

Passar o que é x de um lado e o que é número do outro lado.

$-7x = - \frac{47}{2} + 2,50$

A fração 47/2 corresponde a 23,5. É mais interessante para nós, nesse caso, utilizar o valor decimal.

$-7x = - 23,5 + 2,50$

Somar logo.

$-7x = -21$

Podemos multiplicar por -1 para tirar os sinais negativos.

$7x = 21$

Passar o x dividindo

$x = \frac{21}{7}$

Dividir

$\boxed{x = 3}$

Para um preço de R$ 2,50, a quantidade demandada é de 3 unidades.

B) Basta igualar as duas formulinhas.

$5x - \frac{1}{2} = -7x + \frac{47}{2}$

Passar o que é x de um lado e o que é número do outro lado.

$5x + 7x = \frac{47}{2} + \frac{1}{2}$

Somar tudo. Como as frações têm o mesmo denominador, <u>nada de </u><u>mmc</u>! Basta somar os numeradores.

$12x = \frac{48}{2}$

Podemos dividir lá, olha:

$12x = 24$

Passar o x dividindo

$x = \frac{24}{12}$

Dividir

$\boxed{x = 2}$

O ponto de equilíbrio é o valor 2.

C) Basta, então, igualar as fórmulas da oferta e da demanda a 10.

Fórmula da oferta

$10 = 5x - \frac{1}{2}$

Passar o que é x de um lado e o que é número do outro lado.

$5x = 10 - \frac{1}{2}$

Se 1/2 = 0,5, dá pra resolver sem fazer mmc:

$5x = 10 - 0,5$

Subtrair

$5x = 9,5$

Passar dividindo

$x = \frac{9,5}{5}$

Dividir.

$\boxed{x = 1,9}$

Fórmula da demanda

$10 = -7x + \frac{47}{2}$

Passar o que é x de um lado e o que é número do outro lado.

$-7x = \frac{47}{2} - 10$

Divide 47/2, vai.

$-7x = 23,5 - 10$

Subtrair.

$-7x = 13,5$

Passar o 7 dividindo.

$x = - \frac{13,5}{7}$

Vamos dividir e transformar em decimal.

$\boxed{x = -1,9285714285714285714285714285714}$

Subtrair a oferta pela demanda.

$x = 1,9 - (-1,9285714285714285714285714285714)$

Subtrair.

$\boxed{x = 3,8285714285714285714285714285714}$

Arredondando, o preço será de R$ 3,83.

8 0

3 years ago

Can someone pls help me? I don’t really get this

Marta_Voda [28]

What is it? The question?

8 0

3 years ago

A rectangle hale card has a length of 3/10 and a width of 4/5 find the perimeter

postnew [5]

Answer:

22/10 or 2 and 1/5

Step-by-step explanation:

To find the perimeter, add all sides together. Since it's a rectangle, the other sides are the same measurement as the ones given. Add 3/10, 3/10, 4/5, and 4/5 together. To do this, find a common denominator. The lowest common denominator is 10 so multiply the 4/5 by 2/2 to get the denominator to be 10. Now, add 3/10, 3/10, 8/10, and 8/10. It adds up to 22/10 but if you don't want an improper fraction, simplify it to 2 and 1/5.

4 0

4 years ago

Assume that price is an integer variable whose value is the price (in US currency) in cents of an item. Assuming the item is pai

cestrela7 [59]

Answer:

$Change = (Paid*100) - Price$

Step-by-step explanation:

First of all we need to know the relation between 1 dollar and 1 cent in order to express everything in the units required in the question.

We know that $1 dollar = 100 cents$ , so the amount paid for the item with single dollars has to be multiplied by 100 to express its value in cents.

$Paid_{cents}=Paid_{dollars}*100$

Now that we have everything in cents, we can make the subtraction:

$Change_{cents} = Paid_{cents} -Price_{cents}$

Replacing the value in cents we get:

$Change = (Paid*100) - Price$

4 0

3 years ago

A collection of five coins has a value of $1 and consists of dimes and

DENIUS [597]

For this case we propose a system of equations. We have to:

x: Let the variable that represents the number of dimes

y: Let the variable that represents the number of quaters

We know that:

One dime equals 10 cents, $0.10

A quater equals 0.25 cents, $0.25

According to the statement we have:

$x + y = 5\\0.10x + 0.25y = 1$

We multiply the first equation by -0.10:

$-0.10x-0.10y = -0.5$

We have the following equivalent system:

$-0.10x-0.10y = -0.5\\0.10x + 0.25y = 1$

We add the equations:

$-0.10x + 0.10x-010y + 0.25y = -0.5 + 1\\0.15y = 0.5\\y = \frac {0.5}{0.15}\\y = 3.33$

Approximately 3 quater coins

$x = 5-y = 5-3 = 2$

And two dimes

Answer:

3 quater

2 dimes

4 0

3 years ago