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Paraphin [41]
3 years ago
14

Solve for the given variable (see pic)

Mathematics
2 answers:
Zanzabum3 years ago
8 0
Isolate the a. Note the equal sign. What you do to one side, you do to the other.

Subtract 27 from both sides to isolate the a.

a + 27 (-27) = 32 (-27)

a = 32 (-27)

Subtract

a = 5

5 is your answer


hope this helps
4vir4ik [10]3 years ago
7 0
27+a=32
a=32-27
a=5


Hope this helped you :)
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The lifetimes of a certain type of light bulbs follow a normal distribution. If approximately 2.5% of the bulbs have lives excee
spin [16.1K]

Answer:

Mean = 339 hours

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Step-by-step explanation:

We are given that approximately 2.5% of the bulbs have lives exceeding 445 hours

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P(x<445) =1- 0.025 =0.975

 z value for 0.975 is 1.96

Formula : z=\frac{x-\mu}{\sigma}

So, 1.96=\frac{445-\mu}{\sigma}

1.96 \sigma =445-\mu--A

Now we are given that  approximately 16% have lives exceeding 393 hours,

So,P(x>393) = 0.16

P(x<393) =1- 0.16 =0.84

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Formula : z=\frac{x-\mu}{\sigma}

So, 1=\frac{393-\mu}{\sigma}

1 \sigma =393-\mu ---B

Solve A and B

Substitute the value of \sigmafrom B in A

1.96 (393 -\mu) =445-\mu

770.28 -1.96\mu=445-\mu

770.28 -445=1.96\mu-\mu

325.28=0.96\mu

\frac{325.28}{0.96}=\mu

338.83=\mu

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\sigma =393-338.83

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5 0
3 years ago
6 x 10^9 divide 3x10^4 = ____x10^?
lara [203]

Answer:

2 × 10⁵

Step-by-step explanation:

The following data were obtained from the question:

6×10⁹/ 3×10⁴ =?

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Recall:

Aᵐ ÷ Aⁿ = Aᵐ ¯ ⁿ

Therefore,

6×10⁹ ÷ 3×10⁴ = (6/3) × 10⁹ ¯ ⁴

6×10⁹ ÷ 3×10⁴ = 2 × 10⁵

Thus, 6×10⁹/ 3×10⁴ is equal to 2 × 10⁵

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3 years ago
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Assuming that the ball is launch from the ground. the initial velocity would be equal to its final velocity when it reach the ground. this is because the acceleration due to gravity is working on the ball, when it goes up decelerates up to zero, then falls back then acceleartes again until it reach the groun, where the velocity is 150 m/s
7 0
4 years ago
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What is the solution set for X-3&gt;1?
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