<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
our X is 30 because 3x = 90 and if we divide that by 3 then we are left with 30, I knew it was equal to 90 degrees because of the little red box that symbolizes a 90 degree angle.
So now that we know X = 30 we can plug it in for (2x + 3y)
2(30) + 3y is equal to (60 + 3y) and if we equal that to the other side 3x and plug in for x on that side, we have a new equation of 90 = 60 + 3y so then from here we subtract 60 from both sides and are left with 30 = 3y and finally we divide 3
and our final answer is Y = 10 (((((((((((((((((((((((((((((:
One answer would be15669012
Hope this helps I got (-1, 7)
Answer:
19.
Step-by-step explanation:
PEMDAS.
3^2=9
5 x 2 + 9
10 + 9 = 19
