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2 years ago

10) Use the equation x2 + 8x = 9 to answer the following questions (1 point for each part, 2 points total). .

Mathematics

1 answer:

GREYUIT [131]2 years ago

8 0

Answer:

i might be wrong but i think its 10

Step-by-step explanation:

x2+8x=9

collet terms

10x=9

divide both side by 10

x = 9/10

alternative form

x = 0.9

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2. A fair dice is rolled. What is the probability that a number divisible by 3 is rolled?

Anni [7]

Answer: 2

Step-by-step explanation:

A dice has 6 numbers on it, 1,2,3,4,5, and 6.

how many pairs of 3 can you make?

(1 2 3) (4 5 6)

There are 2 pairs, so your answer is 2

6 0

3 years ago

A truck that can carry no more than 7100 lb is being used to transport refrigerators and upright pianos. Each refrigerator weigh

pishuonlain [190]

Let x be the number of refrigerators

Y be the number of pianos

So the inequality:

300x + 475y < 7100

So substitute 12 and 8 to the inequality

300(12) + 475(8) < 7100

3600 + 3800 < 7100

7400 < 7100 is not true

So it will overload the truck

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2 years ago

Three improper fractions for 4 1/2

Brut [27]

9/2, 18/4, 27/6 you just make a equivalent fraction then multiply the whole number by the denominator and add the numerator

7 0

2 years ago

Read 2 more answers

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

3 years ago

The width of a rectangle measures (5v-10w)centimeters, and its length measures (2v+3w)centimeters. Which expression represents t

kiruha [24]

Answer:the perimeter of the rectangle =A) (−14w+14v) centimeters

Step-by-step explanation:

Step 1

The perimeter of a Rectangle is given as 2 (l+ w)

If Length = 2v+3w centimeters.

and width =5v-10wcentimeters

Then Perimeter =2 (2v+3w + 5v-10w)

Perimeter=2(7v -7w)

Perimeter= 14v - 14w or can be written as -14w +14v

8 0

2 years ago