<span>A. 54°; acute is the answer</span>
2/12, 3/18, 4/24
Hope this helps
Since y = 5x-1, we can fill it into 3x + 3y = -3. First, let's look at relating to a simpler equation. Let's say that x + y = 9 and y = 3 + 5. Now, we can fill it in to get that x + (3 + 5) = 9. Now, we know that 3+5 is 8, so x + 8 = 9. Now, x = 1. Likewise, we can do the same. For 3x + 3y = -3, all we need to do is to switch the y in 3x + 3y = -3 with 5x - 1. So it would become 3x + 3(5x - 1) = -3. Now we distribute to get 3x + 15x - 3 = -3. Now add three to both sides to get 3x + 15x = 0. Now simplify to get 18x = 0. Now we know that x = 0. Now fill x into y = 5x - 1. So y = 5(0) - 1. Now we know that y = -1.
To check fill in the answer to 3x + 3y = -3.
3(0) + 3(-1) = -3
0 + (-3) = -3
0 - 3 = -3
-3 = -3
Now that our check is completed we now know that x is 0 and y is -1.
Use order of operations PEMDAS
P- parenthesis
E-exponent
M-multiply
D- division
A-addition
S-subtraction
Simplify in this order
Answer:
See below.
Step-by-step explanation:
You differentiate top and bottom of the fraction until substitution gives you a value.
I can do the third one for you:
Lim x --> 0 of sin2x / sin3x
= lim x --> 0 of 2 cos2x / 3 cos 3x
= 2 cos 0 / 3 cos 0
= 2/3.
Limit as x--> 0 of (e^x - (1 - x) / x
= limit as x --> 0 of e^x + x - 1 / x
= lim (e^x + 1) / 1
= 1 + 1 / 1
= 2.
limit as x--> 00 of 3x^2 - 2x + 1/ (2x^2 + 3)
= limit as x --> 00 of 6x - 2 / 4x ( 00 = infinity)
Applying l'hopitals rule again:
limit is 6 / 4 = 3/2.
Limit as x --> 00 of (ln x)^3 / x
= limit 3 (Ln x)^2 ) / x
= limit of 6 ln x / x
= limit 6 / x
= 0.
We had to apply l'hopitals rule 3 times here,
