This is going to take a while..
1. 2AgI + Na2S --> Ag2S + 2NaI
2. Na3PO4 + 3HCl --> 3NaCl + N3PO4
3. Ba3N2 + 6H2O --> 3Ba(OH)2 + 2NH3
4. TiCl4 + 2H2O --> TiO2 + 4HCl
5. 3CaCl2 + 2Na3PO4 --> Ca3(PO4)2 + 6NaCl
6. 2NaBr + Cl2 --> 2NaCl + Br2
7. Mg(OH)2 + 2HCl --> MgCl2 + 2H2O
Hopefully that helps.
Your experimental value would not be accurate
The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions,
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂
The option that would be appropriate to model nuclear fission is disturbing a drop of water such that it breaks into smaller droplets
Nuclear fission refers to the splitting of a heavy nucleus into lighter nuclei owing to the bombardment of small particle.
The liquid drop model provides the most apt model for describing the concept of nuclear fission. In nuclear fission, the nucleus breaks due to the increase in repulsion between the nuclear charges.
As the size of the nucleus continues to increase, any little disruption will; result in the breaking up of the nucleus into smaller fragment called daughter nuclei.
Hence, the model of disturbing a drop of water such that it breaks into smaller droplets is the most apt description of nuclear fission.
Learn more: brainly.com/question/13440572
