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Blizzard [7]
3 years ago
13

5. What happens to the average kinetic energy of water molecules as water freezeslt decreases as the water absorbs energy from i

ts surroundingsA B lt increases as the water absorbs energy from surroundings.its C It increases as the water releases energy to its surroundings. D. It decreases as water releases energy to its surroundings.

Chemistry
2 answers:
Basile [38]3 years ago
6 0

Answer:

D. It decreases as water releases energy to its surroundings.

Explanation:

Kinetic energy is the energy associated with the speed of a body. If there is speed, surely there will be that kind of energy. For objects that are at rest, the kinetic energy is zero because the velocity of such bodies is zero.

Water molecules in liquid form are in constant motion, the greater the motion of these molecules the greater the kinetic energy in this system. However, as water moves from the liquid to the solid state, the velocity of the molecules begins to slow down and the energy begins to be released by the edges. From this we can conclude that in the solid state the kinetic energy of water decreases as water releases energy into the surroundings.

4vir4ik [10]3 years ago
3 0
The correct answer among the choices listed above is option D. The average kinetic energy of water molecules as water freeze <span>decreases as water releases energy to its surroundings. Energy is released as the molecules go into a more condensed phase which is the solid.</span>
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The standard reduction potentials for the Ag+|Ag(s) and Zn2+| Zn(s) half-cell reactions are +0.799 V and -0.762 V, respectively.
mihalych1998 [28]

<u>Answer:</u> The potential of the given cell is 1.551 V

<u>Explanation:</u>

The given chemical cell follows:

Zn(s)|Zn^{2+}(0.125M)||Ag^{+}(0.240M)|Ag(s)

<u>Oxidation half reaction:</u> Zn(s)\rightarrow Zn^{2+}(0.125M)+2e^-;E^o_{Zn^{2+}/Zn}=-0.762V

<u>Reduction half reaction:</u> Ag^{+}(0.240M)+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.799V       ( × 2)

<u>Net cell reaction:</u> Zn(s)+2Ag^{+}(0.240M)\rightarrow Zn^{2+}(0.125M)+2Ag(s)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.799-(-0.762)=1.561V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Zn^{2+}]}{[Ag^{+}]^2}

where,

E_{cell} = electrode potential of the cell = ? V

E^o_{cell} = standard electrode potential of the cell = +1.561 V

n = number of electrons exchanged = 2

[Zn^{2+}]=0.125M

[Ag^{+}]=0.240M

Putting values in above equation, we get:

E_{cell}=1.561-\frac{0.059}{2}\times \log(\frac{(0.125)}{(0.240)^2})

E_{cell}=1.551V

Hence, the potential of the given cell is 1.551 V

6 0
3 years ago
Can some help me with this i really don't under stand it you can Have brainliest
PilotLPTM [1.2K]

Answer:

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8 0
3 years ago
Determine which equations you would use to solve the following problem: Calculate the amount of heat needed to change 20.0 g of
Inessa [10]

Answer:

Q = 4019.4 J

Explanation:

Given data:

Mass of ice = 20.0 g

Initial temperature = -10°C

Final temperature = 89.0°C

Amount of heat required = ?

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specific heat capacity of ice is 2.03 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT =  89.0°C - (-10°C)

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3 0
3 years ago
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AB\rightarrow A+B

In general, a single displacement reaction looks like:

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Fourth reaction is single replacement reaction as bromine is replaced by chlorine.

So, the correct choice is the last reaction, Cl_2+2KBr\rightarrow 2KCl+Br_2 .

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