According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
Hello there the answer to your question would be 60. Since 150-(60%*150) = 150 - 60 *150 = (1-60%)*150 = (100%-60%) * 150= 40% * 150 = 40/100 * 150 = 40 * 150 ÷ 100 = 6000/100 = 60. Hope this helps you out, have a great day!
The solution to the inequality is -20.8 > p (imagine the symbol is the symbol for at least)
Answer:
61.25%
Step-by-step explanation:
How many ml of 20 percent acid should be added to pure acid
to make 70 ml of 30 percent acid?
:
let x = amt of 20% mixture
then
(70-x) = amt of pure acid
:
0.20x + (70-x) =0 .30(70)
0.20x + 70 - x = 21
= 21 - 70
-0.8x =-49
x = 61.25%
x = +61.25 ml of 20% stuff
