Hey!
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Steps To Solve:
4.6(x - 3) = -0.4x + 16.2
~Distributive property
4.6x - 13.8 = -0.4x + 16.2
~Add 0.4 to both sides
4.6x - 13.8 + 0.4= -0.4x + 16.2 + 0.4
~Simplify
5x - 13.8 = 16.2
~Add 13.8 to both sides
5x - 13.8 + 13.8 = 16.2 + 13.8
~Simplify
5x = 30
Divide 5 to both sides
5x/5 = 30/5
~Simplify
x = 6
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Answer:

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Hope This Helped! Good Luck!
Answer:
there is one real solution
Step-by-step explanation:
use the quadratic formula. what is in the square root is called the discriminant.
since it came out to 0 there is one real solution
The ratio of the number of sundaes with nuts to the number of sundaes without nuts is 11/14
What is ratio?
Ratio is a quantitative relationship between two values indicating the number of times one value contains within the other value
In other words, we are expressing the number of sundaes with nuts as a fraction of the ones without nuts
There are 22 sundaes with nuts
number of sundaes without nuts=50-22
number of sundaes without nuts=28
sundaes with nuts/sundaes without nuts=22/28
2 is common to both numbers
sundaes with nuts/sundaes without nuts=11/14
Find out more about ratio on:brainly.com/question/2328454
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The number 12,300 is written 1.23 x 10⁴ as a scientific notation. It's coefficient is 1.23; base is 10⁴ in exponent form.
Scientific notation is a method developed by scientists to shorten the number that expresses a very large number. The scientific notation is based on powers of the base number 10.
Scientific notation has two numbers: coefficient and base. The coefficient must be greater than or equal to 1 and less than 10. The base is always 10 written in exponent form.
12,300 as coefficient in standard form in scientific notation.
1) put decimal after the first digit and drop the zeros. from 12,300 to 1.23 this is the coefficient.
2) to find the exponent, count the number of places from decimal to the end of the number.
1.2300 ; there are 4 places
So the scientific notation is 1.23 x 10⁴
D midpoint of EC -----------------> FD parallel to AC and FD=AC/2=14/2=7
<span>2-EB=EA E midpoint of AB </span>
<span>DB=DC D midpoint BC ...............> ED=AC/2=2 </span>
<span>3-T midpoint of SR </span>
<span>U midpoint of QR ---------> TU = QS/2 </span>
<span>QS=2 TU = 4.4 </span>
<span>4- The same steps SR=2 UV=9 </span>
<span>5-N midpoint of KM </span>
<span>O midpoint of ML </span>
<span>* NO parallel to Kl</span>