Assumptions:
1. Equilibrium has been reached for the allele proportions
2. Absence of <span>evolutionary influences such as </span>mate choice<span>, </span>mutation<span>, </span>selection<span>, </span>genetic drift<span>, </span>gene flow<span> and </span>meiotic drive<span>.
</span>
Defining L=long stem, l=short stem, and L is dominant over l.
f(x) = frequency of allele x (expressed as a fraction of population)
Then the Hardy-Weinberg equilibrium law applies:
p^2+2pq+q^2=1
where
f(LL)=p^2
f(Ll)=2pq
f(ll)=q^2
Given f(ll)=0.35=q^2, we have
q=sqrt(0.35)=0.591608
p=1-q=0.408392
=>
f(Ll)
=2pq
=2*0.408392*0.591608=0.483216
= proportion of heterozygous population
Answer: percentage of heterozygous population is 48.32%
You are correct the answer is c
I need to see the chart to answer you
Answer:
First picture (of baby and parents) is reproduction, the third picture (kid at doctor) is growth, I'm not sure about the others.
Explanation:
C. rocky surface (<span>rocky surfaces roughly similar to desert and mountainous areas on the earth)</span>
