You would find the multiples 2 and 3 had in common
so may 6th, 12th, and 18th
2: 3:
4 6*
6* 9
8 12*
10 15
12* 18*
14
16
18*
The number exists 99, then 99 - 49 = 50
Therefore, the pair of two-digit numbers exist between 99 and 49.
<h3>What is the difference?</h3>
In math, the word difference exists as the outcome of subtracting one number from another.
Let the first pair of two-digit numbers be xy and the second pair of numbers be yx.
we want a two-digit number, a two-digit number begins from 10 and ends with a two-digit number that exists 99.
Let the difference of 50 exists possible when we take the biggest two-digit number
Therefore, the number exists 99
99 - 49 = 50
Therefore, the pair of two-digit number exists 99 and 49.
To learn more about differences refer to:
brainly.com/question/14335054
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Answer:
i think the answer is C
Answer:
It can either be 17593pi/9000 rad or if youre looking for a decimal answer is it 1.95pi and rad=6.14
Step-by-step explanation:
<span>2x + y = 3
a: 5
x - 2y = -1
a: 2
If equation one is multiplied by 2 and then the equations are added, the result is _____.
3x = 2 this is the answer
3x = 5
5x = 5</span>