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2 years ago

Find the equation whose graph is shown below. Write your answer in standard form.

Mathematics

1 answer:

vladimir2022 [97]2 years ago

5 0

Answer:

it as a liner function that is why we should choose to point in order to find the liner equation

y=2/3x+1

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HELP FAST PLEASE Twenty is what percent of 200 10% 80% 20% 40%

mrs_skeptik [129]

10%

200 x x%=20
x=10%

Do u understand ?

4 0

3 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

3 years ago

HELP ME PLEASE!!! I NEED HELP!

alexandr1967 [171]

For the whole numbers:

5 0

3 years ago

Read 2 more answers

Goldbach''s Conjecture is a famous conjecture that has never been proven true or false. The conjecture states that every even nu

zhannawk [14.2K]

Has been proven TRUE.... hope it helps buddy have a great day hope you pass

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3 years ago

Read 2 more answers

If You can pls answer all 4 with the equations

Trava [24]

9514 1404 393

Answer:

69
100
-24
1/729

Step-by-step explanation:

Put the numbers where the variables are and do the arithmetic. Your calculator can help.

1. 6x -2y +5y = 6(10) -2(3) +5(3) = 60 -6 +15 = 69

2. add 16 to find x.

x -16 = 29

x = 45

Then do the substitution:

2(45 +5) = 2(50) = 100

3. 3(4²) -4(18) = 3(16) -4(18) = 48 -72 = -24

4. (1/9)³ = (1/9)(1/9)(1/9) = 1/(9·9·9) = 1/729

8 0

3 years ago