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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics

2 answers:

siniylev [52]3 years ago

8 0

No yes yes yes no ; sol. when x=4 , f(x) = 0 ,so (x-4) is right answer.....

rewona [7]3 years ago

3 0

Answer: YES → (x + 2) (x - 4) (x + 4)

NO → (x - 2) (x + 6)

<u>Step-by-step explanation:</u>

The best way to answer this question is to factor the given polynomial and then look at the choices at the botom of your screeen.

f(x) = x³ + 2x² - 16x - 32

0 = x³ + 2x² - 16x - 32

= x²(x + 2) -16(x + 2)

= (x + 2)(x² - 16)

= ↓ (x - 4)(x + 4)

= (x + 2)( x - 4)(x + 4)

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A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

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3 years ago

Evaluate the expression for b = 7<br> 6b + 8 – 5b

bearhunter [10]

Answer:

For b = 7, the expression equals 15.

Step-by-step explanation:

6b + 8 - 5b

Substitute the variable b = 7.

6(7) + 8 - 5(7)

Multiply.

42 + 8 - 35

Add.

50 - 35

Subtract.

15.

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2 years ago

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STatiana [176]

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