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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics

2 answers:

siniylev [52]3 years ago

8 0

No yes yes yes no ; sol. when x=4 , f(x) = 0 ,so (x-4) is right answer.....

rewona [7]3 years ago

3 0

Answer: YES → (x + 2) (x - 4) (x + 4)

NO → (x - 2) (x + 6)

<u>Step-by-step explanation:</u>

The best way to answer this question is to factor the given polynomial and then look at the choices at the botom of your screeen.

f(x) = x³ + 2x² - 16x - 32

0 = x³ + 2x² - 16x - 32

= x²(x + 2) -16(x + 2)

= (x + 2)(x² - 16)

= ↓ (x - 4)(x + 4)

= (x + 2)( x - 4)(x + 4)

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Increase £30 by 15% what is the answer

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3 years ago

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

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3 years ago

Could someone check my answer please . Thank you

Elodia [21]

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3 years ago

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