We will get the number of possible selections, and then subtract the number less than 25 cents.
We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.
That's 5*4*3 = 60 selections
Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels.
To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2 on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).
If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.
And there is 1 other selection less than 25 cents, 2 dimes and no nickels.
So that's 4+3+1 = 8 selections which we must subtract from the 60.
Answer 60-8 = 52 selections of coins worth 25 cents or more.
You have the right answer. n + p = m because inside angle + inside angle = outside angle.
The answer is 35 i think but i am not sure
Answer:
s=4& c=7
Step-by-step explanation:
3(4)+9(7)=$75
8(4)+5(7)=$67
Answer:
No
Step-by-step explanation:
21 = 3p - 5
<u>Step 1</u> : Add 5 on both sides
21 + 5 = 3p
26 = 3p
3p = 26
<u>Step 2</u> : Divide 3 on both sides
p = 26/3
Hence, the solution of the given equation is 26/3, not 9.
