Need to do the 2^3 first
answer is A
There are four 7's in a standard card. Chance of getting a 7 first is 4/52 = 1/13
There are four queens in a standard card. Chance of getting a queen in the second drawing is 4/51 and chance of getting a queen in the third drawing is 3/50.
Therefore, chance of drawing a seven and two queens is 1/13 x 4/51 x 3/50 = 2/5525
Answer: 1/4, 0.3, 45%
Step-by-step explanation:
1.) 1/4= 25% probability (0-19 home runs)
2.) 0.3= 30% Probability (40+ home runs)
3.) 45% = 45% Probability (20-39 home runs)
It would be 7500 because if you divide 75000/10 your answer would be 7500
Fu/ac=mu/bc so 27/36=mu/24 so mu= 18