Yes, an example includes 1 and any number that exists.
Answer:
8280
Step-by-step explanation:
You would multiply 7200 by .15 and then add it back to 7200.
What u can do is do 3/63=5/x. so u have to get x all by itself.
3/63=5/x
cross multiply
63×5 and 3×x
315=3x
divide by 3 to the number 315
ANSWER:105
Answer:
<h2>1</h2>
Step-by-step explanation:
0.72/0.36 x 2
0.72/0.72
1
I'm always happy to help :)
