Question

1) Factor the expression and use the fundamental identities to simplify. There is more than one correct form of the answer.

Answer 1

Answer:

Step-by-step explanation:

1) 6 tan2x − 6 tan2x sin2x

=$6tan2x(1-sin2x)\\= 6tan2x (sin^2 x + cos^2 x -2sinx cosx)\\= 6tan2x (sinx+cosx)^2$

2) $\frac{3}{1+cos x} +\frac{3}{1-cosx} \\=\frac{3-cosx+3+cosx}{1-cos^2 x} \\=\frac{6}{sin^2 x} \\=6 cosec^2 x$

3) $\frac{sin^2 y}{1-cosy } =\frac{1-cos^2 y}{1-cosy }\\=1+cosy$

4) x=6cos t

So cost =x/6

$sint = \frac{\sqrt{36-x^2} }{\{6 }$

so -3sint

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