There is no restrictions for x for f(x) =3✓x because you can take the cube root of any real numbers. Therefore, the domain is infinity she. dealing with the set of real numbers.
You can't take the square root of negative numbers. So, x values are restricted for f(x) = ✓x for real numbers and the domain is (0, infinity).
<h3>How to explain the domain?</h3>
It should be noted that since x cannot take negative values in the question, the square root he undefined. Hence it is an imaginary value.
Also, You can't take the square root of negative numbers. So, x values are restricted for f(x) = ✓x for real numbers and the domain is (0, infinity).
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Answer:
r= 0.899m
Step-by-step explanation:
A= 
r²
r=√A/
24.5 Celsius.
<span>
</span>The temperature t in degreen Celsius is equal to the temperature T in the degrees Fahrenheit minus 32, times 5/9
<span>The name of the shape graphed by the function r ^ 2 = 9
cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a
plane curve with a feature shape which consists of two loops that meet at a
central point. The curve is also sometimes called as the lemniscate of
Bernoulli. </span>
Explanation:
The
period of coskθ is 2π/k. In this case, k = 2 therefore the
period is π.
r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily
one period can be chosen as θ ∈
[0, π] wherein cos 2θ ≥0.
As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.
Also,
as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the
vertical θ = π/2
A
Table for half period [0,π4/] is
adequate for the shape in Quarter1
Use symmetry for the other three quarters:
(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>
