C would be the correct answer.
When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.
The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.
The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.
We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.
Parents: BB x Bb
Gametes: B, B, and B, b
Offspring: BB, BB, Bb, Bb
The genotypic ratio = 1:1
The phenotypic ratio = 1:0
Genotype probabilities:
P(BB) = 2/4 = 0.5 or 50%
P(Bb) = 2/4 = 0.5 or 50%
Learn more about genotype here:
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Answer: Your answer is indeed <u>A. Fair treatment.</u>
Hope this helps!
<span>The person who has a small intestine that has fewer villi than normal would most likely be u</span>nderweight. The villi of the small intestines are the small structures that do the absorbing of the nutrients. Having less of these structures, less nutrients are absorbed and the person is more likely to be malnourished.
Answer:B.
It was used to prove that smoking causes health problems.
Explanation:
