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AleksandrR [38]
3 years ago
14

Answer quickly, thx plz

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

The last option is the answer for your question


KonstantinChe [14]3 years ago
4 0

y= x6. 2 times 6 is 12. 4 times 6 is 24. and so on

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Jerry left a ​$3. tip on a meal that cost ​$35. What percent of the​ meal's cost was the​ tip? What was the total cost of the me
Brums [2.3K]
3/35 = 0.0857 = 8.57% <== percent of the tip

35 + 3 = 38 <== total cost
4 0
3 years ago
H - 9 = 7 <br> explain how you found h
makkiz [27]

Answer:

h=16

Step-by-step explanation:

h-9=7

h=9+7

h=16

I hope this helps.

6 0
3 years ago
Read 2 more answers
Identify the solution and graph of the given inequality.<br> p 5/14<br> p &lt; 4/7
Dvinal [7]

Answer:

p > 5/14

Step-by-step explanation:

4 0
3 years ago
0.3(4-x)=x-1.4 how do you solve this problem?
tresset_1 [31]

Answer:

x = 2.

Step-by-step explanation:

Solve for x:

0.3 (4 - x) = x - 1.4

Expand out terms of the left hand side:

1.2 - 0.3 x = x - 1.4

Subtract x from both sides:

1.2 + (-0.3 x - x) = (x - x) - 1.4

-0.3 x - x = -1.3 x:

-1.3 x + 1.2 = (x - x) - 1.4

x - x = 0:

1.2 - 1.3 x = -1.4

Subtract 1.2` from both sides:

(1.2 - 1.2) - 1.3 x = -1.2 - 1.4

1.2 - 1.2 = 0:

-1.3 x = -1.2 - 1.4

-1.2 - 1.4 = -2.6:

-1.3 x = -2.6

Divide both sides of -1.3 x = -2.6 by -1.3:

(-1.3 x)/(-1.3) = (-2.6)/(-1.3)

(-1.3)/(-1.3) = 1:

x = (-2.6)/(-1.3)

(-2.6)/(-1.3) = 2.:

Answer:  x = 2.

4 0
3 years ago
Write the standard equation of a circle with center (-2,5) and the point (4,13) on the circle ​
n200080 [17]

since the point (4,13) is on the circle, then the distance from the center to it, is the radius of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{13})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[4-(-2)]^2+[13-5]^2}\implies r=\sqrt{(4+2)^2+(13-5)^2} \\\\\\ r=\sqrt{36+64}\implies r=\sqrt{100}\implies r=10 \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-2}{ h},\stackrel{5}{ k})\qquad \qquad radius=\stackrel{10}{ r}\\[2em] [x-(-2)]^2+[y-5]^2=10^2\implies (x+2)^2+(y-5)^2=100

6 0
3 years ago
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